You said X = (5y+1) / (y-2)
Multiply each side by (y-2):
X(y-2) = (5y+1)
Eliminate parentheses:
Xy - 2X = 5y + 1
Add 2X to each side:
Xy = 5y + 1 + 2X
Subtract 5y from each side:
(X-5)y = 1 + 2X
Divide each side by (X-5):
<em>y = (1+2X) / (X-5) </em>
Answer:
3x + 2x2 + 4 = 5
3x + 2x2 + 4 – 5 = 5 – 5
First be sure that the right side of the equation is 0. In this case, all you need to do is subtract 5 from both sides.
3x + 2x2 – 1 = 0
2x2 + 3x – 1 = 0
Simplify, and write the terms with the exponent on the variable in descending order.
2x2
+
3x
–
1
=
0
↓
↓
↓
ax2
bx
c
a = 2, b = 3, c = −1
Now that the equation is in standard form, you can read the values of a, b, and c from the coefficients and constant. Note that since the constant 1 is subtracted, c must be negative.
Answer
2x2 + 3x – 1 = 0; a = 2, b = 3, c = −1
Step-by-step explanation:
The standard form of a quadratic equation is
,
where 
, 
, and 
are coefficients. You want to get the given equation into this form. You can accomplish this by putting all the non-zero values on the left side on the equation.
In this case, the given equation is
Since 
is on the right side of the equation, we subtract that from both sides. The resulting equation is
Looking at the standard form equation , we can see that
Answer:
11 17/21
Step-by-step explanation:
Six thirty-five...............................
