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kolbaska11 [484]
3 years ago
5

Evaluate sin(cos^-1(-15/17))

Mathematics
2 answers:
Sonja [21]3 years ago
8 0

cos⁻¹ a = arccos a

↓

sin(cos⁻¹ (-15/17)) = sin(arccos(-15/17))

sin(arccos(x))=\sqrt{1-x^{2}}

↓

sin(arccos(-\frac{15}{17})=\sqrt{1-(-\frac{15}{17})}   =\sqrt{1-\frac{225}{289}}  =\sqrt{\frac{64}{289}}  =\frac{8}{17}

ANSWER : 8/17

Verizon [17]3 years ago
4 0

Hello!

First of all, let's find the arcosine (cos^-1) of (-15/17)

cos^-1(-15/17)≈-28.1

Now we find the sine of this number.

sin-28.1≈0.47

Therefore, our answer is about 0.47

I hope this helps!

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