0.7 is 10 times as much as

A triangle weighs 3 grams and a circle weighs 6 grams. Find the weight of a square in Hanger A and the weight of a pentagon in H

Zanzabum

Answer:

Equation of Hanger A:

x + y = z

z = 9 grams

Equation for hanger B

x + y = p

p = 9 grams

Step-by-step explanation:

Note: This question is not complete, and lacks necessary data to answer this question. But for the sack of concept, we wil be solving this question using our own data.

Data given:

Triangle weight = 3 grams

Circle weight = 6 grams

There are two hangers A and B.

We have to find weight of the square in Hanger A and weight of the pentagon in Hanger B.

So, for your understanding I have drawn the two hangers A and B. In A we have triangle and circle on the LHS and the square on the right. On the other hand, we have pentagon on the right and triangle and circle.

Sketch is attached in the attachment.

Let's suppose: Hanger A is balanced, So,

Triangle weight = 3 grams = x

Circle weight = 6 grams = y

weight of the pentagon in Hanger B = p

weight of the square in Hanger A = z =?

So,

Equation of Hanger A:

x + y = z

z = 3 + 6

z = 9 grams = weight of the square in Hanger A

Similarly for Hanger B.

Equation for hanger B

x + y = p

p = 3 + 6

p = 9 grams

6 0

3 years ago

X + 12/x + 2 = x/x + 8<br> A) X = -4<br> B) X = 8<br> C) X = 6<br> D) X = -6

xxMikexx [17]

I got x = 96/18 i dont think the answer is there

4 0

3 years ago

For which of the following graphs would NOT make sense to connect the points?

jeka94

Answer:

i believe d. I could be wrong

Step-by-step explanation:

5 0

3 years ago

PLEASE HELP ASAP ON MY MATH!!

Allisa [31]

Answer:

Area of shaded region=41 square feet

Area of non shaded region= 87 square feet

Step-by-step explanation:

As, Shaded area is made of different shapes including two rectangles and one triangle

So,

Area of shaded region,

$=(8\times2)+(10\times 1)+(\frac{1}{2}\times 3\times10)\\\\ =16+10+15=41 \quad \text{square feet}$

Area of non shaded region=total area of rectangular region-Shaded region

$=(16\times 8)-(41)\\=128-41\\=87 \quad \text{square feet}$

7 0

2 years ago

Read 2 more answers

What is the equation of the line that is perpendicular to y, =, 1 over 3 x, 4. And contains the point negative 2, negative 5,?.

Anit [1.1K]

The equation of the line is, $\rm y = 3x + 1$ .

Given that,

The equation of the line is,

$\rm y = \dfrac{1}{3} x+4\\$

And contains the point (-2, -5).

We have to determine,

What is the equation of the line that is perpendicular to the given line?

According to the question,

The equation of the line is,

$\rm = \dfrac{1}{3}x + 4\\$

On comparing with the standard equation of the line y = mx +c.

The slope of the line $m_1$ is 1/3.

When two lines are perpendicular the relation between these slopes is,

$\rm m_1\times m_1 = {-1}\\\\\dfrac{-1}{3} \times m_2 = -1\\\\-1 \times m_2 = -1 \times 3\\\\-m_2 = -3\\\\m_2 = 3$

And line contains the point (-2, -5).

Then,

$\rm y = mx +c \\\\-5 = 3 (-2) + c\\\\-5 = -6+c \\\\c = 6-5 \\\\c = 1$

Therefore,

The equation of the line that is perpendicular to the given line and contains the point (-2, -5) is,

$\rm y = mx +c \\\\y = 3x +1$

Hence, The required equation of the line is, $\rm y = 3x + 1$ .

For more details refer to the link given below.

brainly.com/question/14388443

7 0

3 years ago