Question

20 PTS! Help! How do you solve the following:

Answer 1

Answer: $3x^2-x+2$

Explanation:

The area of a triangle A can be calculated as A=(height)x(base)/2

We know the height is 6x.

We know $A=9x^3-3x^2+6x$

So the equation becomes (using |AC| as the base length):

$9x^3-3x^2+6x = \frac{6x \cdot |AC|}{2}\\\frac{9x^3-3x^2+6x}{3x}=|AC|\\\frac{3x^2-x+2}{1}=|AC|\\|AC|=3x^2-x+2$

The base is $3x^2-x+2$