Ask question

Ask question

All categories

adelina 88 [10]

3 years ago

7

Find and interpret the mean absolute deviation of the data. Round your answer to the nearest tenth, if necessary. The mean absol

ute deviation is . Question 2 The prices differ from the by an average of $.

1 answer:

SSSSS [86.1K]3 years ago

7 0

Answer list the data sets

Step-by-step explanation:

You might be interested in

The average weight of a 7-year old girl is 49 pounds. The average weight of an 11 year old girl is 77 pounds.

Aneli [31]

I only know D. but I'll try to figure out the rest too. D. 9 years old

8 0

3 years ago

Whats the answer to this numeric algebraic expression

Degger [83]

Answer:

a+b+2

Step-by-step explanation:

4 0

2 years ago

Hey can you please help me posted picture of question

Maksim231197 [3]

For this case we have the following equation:
y = x2-4x + 3
Deriving we have the following equation:
y '= 2x-4
We equal zero and clear x:
2x-4 = 0
x = 4/2
x = 2
Substituting in the given equation we have:
y = (2) ^ 2-4 (2) +3
y = 4-8 + 3
y = -1
The vertex will be the ordered pair:
(x, y) = (2, -1)
Answer:
(x, y) = (2, -1)
option B

5 0

3 years ago

Read 2 more answers

Please help asap urgent <br> brainliest

yKpoI14uk [10]

Answer:

<h2>6 unit cubes</h2>

Step-by-step explanation:

<em>Look at the picture.</em>

7 0

3 years ago

A person stands 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 meters

In-s [12.5K]

Answer:

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

Step-by-step explanation:

Given that,

A person stand 10 meters east of an intersection and watches a car driving towards the intersection from the north at 13 m/s.

From Pythagorean Theorem,

(The distance between car and person)²= (The distance of the car from intersection)²+ (The distance of the person from intersection)²+

Assume that the distance of the car from the intersection and from the person be x and y at any time t respectively.

∴y²= x²+10²

$\Rightarrow y=\sqrt{x^2+100}$

Differentiating with respect to t

$\frac{dy}{dt}=\frac{1}{2\sqrt{x^2+100}}. 2x\frac{dx}{dt}$

$\Rightarrow \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}. \frac{dx}{dt}$

Since the car driving towards the intersection at 13 m/s.

so, $\frac{dx}{dt}=-13$

$\therefore \frac{dy}{dt}=\frac{x}{\sqrt{x^2+100}}.(-13)$

Now

$\therefore \frac{dy}{dt}|_{x=24}=\frac{24}{\sqrt{24^2+100}}.(-13)$

$=\frac{24\times (-13)}{\sqrt{676}}$

$=\frac{24\times (-13)}{26}$

= -12 m/s

Negative sign denotes the distance between the car and the person decrease.

Therefore the rate change of distance between the car and the person at the instant, the car is 24 m from the intersection is 12 m/s.

8 0

3 years ago