1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
kozerog [31]
2 years ago
5

On Monday at work, David produces $w$ widgets per hour, and works for $t$ hours. Exhausted by this work, on Tuesday, he decides

to work for $2$ fewer hours, but manages to produce $4$ additional widgets per hour. If $w = 2t$, how many more widgets did David produce on Monday than on Tuesday?
Mathematics
1 answer:
nasty-shy [4]2 years ago
5 0

Answer:

8 more widgets

Step-by-step explanation:

<u>Monday:</u>

t hours work AT w widgets per hour

So,

total number of widgets = wt

<u>Tuesday:</u>

2 fewer hours than monday, so

hours worked = t - 2

Per hour widget production is 4 more than Monday so:

per hour widget = w + 4

Total number of widgets = (t-2)(w+4)=wt+4t-2w-8

Monday he produced more, so amount more is:

wt-[wt+4t-2w-8]\\wt-wt-4t+2w+8\\-4t+2w+8

Given, w = 2t, we have:

-4t+2w+8\\-4t+2(2t)+8\\-4t+4t+8\\=8

Thus,

8 more widgets were produced

You might be interested in
Logify the problem 5x+2+3=25​
77julia77 [94]
the answer is x=4.
5 0
2 years ago
Borrowed $250
Fittoniya [83]

Answer:

Total interest paid:

$83.73

Total payments:

$333.73

8 0
2 years ago
SQUARE ROOT OF 25<br><br>THANKS ​
guapka [62]

Answer:

5

Step-by-step explanation:

The square roots of 25 are √25=5 and −√25=−5 since 52=25 and (−5)2=25 . The principal square root of 25 is √25=5 .

3 0
3 years ago
Read 2 more answers
1) On a standardized aptitude test, scores are normally distributed with a mean of 100 and a standard deviation of 10. Find the
Musya8 [376]

Answer:

A) 34.13%

B)  15.87%

C) 95.44%

D) 97.72%

E) 49.87%

F) 0.13%

Step-by-step explanation:

To find the percent of scores that are between 90 and 100, we need to standardize 90 and 100 using the following equation:

z=\frac{x-m}{s}

Where m is the mean and s is the standard deviation. Then, 90 and 100 are equal to:

z=\frac{90-100}{10}=-1\\ z=\frac{100-100}{10}=0

So, the percent of scores that are between 90 and 100 can be calculated using the normal standard table as:

P( 90 < x < 100) = P(-1 < z < 0) = P(z < 0) - P(z < -1)

                                                =  0.5 - 0.1587 = 0.3413

It means that the PERCENT of scores that are between 90 and 100 is 34.13%

At the same way, we can calculated the percentages of B, C, D, E and F as:

B) Over 110

P( x > 110 ) = P( z>\frac{110-100}{10})=P(z>1) = 0.1587

C) Between 80 and 120

P( 80

D) less than 80

P( x < 80 ) = P( z

E) Between 70 and 100

P( 70

F) More than 130

P( x > 130 ) = P( z>\frac{130-100}{10})=P(z>3) = 0.0013

8 0
3 years ago
(–4c2 + 7cd + 8d) + (–3d + 8c2 + 4cd) =
BabaBlast [244]

Answer:

4c² + 11cd + 5d

Step-by-step explanation:

(–4c2 + 7cd + 8d) + (–3d + 8c2 + 4cd)

-4c² + 7cd + 8d - 3d + 8c² + 4cd (opening bracket)

8c²-4c²+7cd + 4cd + 8d - 3d

= 4c² + 11cd + 5d

4 0
2 years ago
Read 2 more answers
Other questions:
  • Un11Mid
    8·1 answer
  • How to solve polynomials
    9·1 answer
  • The length of the hypotenuse of a right triangle is 40 centimeters. The legs of the triangle are the same length. How long is ea
    6·1 answer
  • Sigmund wrote four checks last month, and these were the only transactions for his checking account. According to his check regi
    6·2 answers
  • Can someone help me with this ​
    5·1 answer
  • In a probability experiment, Eric flipped a coin 33 times. The coin landed on heads 22 times. What is the ratio of heads to tail
    10·1 answer
  • Solve for y.<br> x+y=7<br> x=4<br> Simplify your answer as much as possible.
    7·2 answers
  • Which of the following equations has no solutions?
    15·1 answer
  • Suppose PQ has one endpoint at
    11·1 answer
  • Evaluate (y+z)2 when y=−3 and z=15.
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!