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lutik1710 [3]
3 years ago
7

Estimate the area of a rectangle with a base length of 3.4 inches and a height of 5.9 inches

Mathematics
1 answer:
Sophie [7]3 years ago
5 0

Answer:

18in^2

Step-by-step explanation:

You can round the 3.4 to a 3 and the 5.9 to a 6.

3×6=18

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Find the absolute maximum and absolute minimum values, if any, of the function. (If an answer does not exist, enter DNE.)f(x) =
lyudmila [28]

Answer:

The absolute minimum value is "-\frac{21}{4}" and the absolute maximum value is "15".

Step-by-step explanation:

Given:

f(x)=x^2-x-5

on,

[0,5]

By differentiating it, we get

⇒ f'(x)=2x-1

Set f'(x)=0

then,

⇒ 2x-1=0

          2x=1

            x=\frac{1}{2} (Critical point)

When x=0,

⇒ f(x)=-5

When x=\frac{1}{2},

⇒ f(x)=-\frac{21}{4} (Absolute minimum)

When x=5

⇒ f(x)=15 (Absolute maximum)

7 0
3 years ago
Solve for the variable x<br><br> m = -12g + x
mario62 [17]

Answer:

x=m+12g

Step-by-step explanation:

m=-12g+x

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x=m+12g

3 0
3 years ago
What is 1.7 as a fraction?
choli [55]
1.7 as a fraction is 17/10

1.(7) the 7 in the parentheses represents the number after the decimal, which is in the tenths spot. 10 tenths + 7 tenths = 17/10 <-- our answer.
3 0
3 years ago
Read 2 more answers
FUNDRAISING A school is raising money by selling calendars for $20 each. Mrs. Hawkins promised a party to whichever of her Engli
____ [38]

Rj, this is the solution to question 19:

• 1st period class sold 60 calendars in total

,

• 2nd period class sold 123 calendars in total

We calculate the average per week, this way:

• 1st period class sold 60/4 = 15 calendars per week

,

• 2nd period class sold 123/4 = 30.75 calendars per week

In consequence the multiplication equation that represents this situation is:

15w + 30.75w = 183, where w is the number of weeks Mrs. Hawkins' classes sold calendars.

This is the solution to question 20:

We already know the average number of calendars that 1st and 2nd period classes sold per week. Now, let's calculate the average for 3nd 4th peiod classes, this way:

• 3rd period class sold 89 calendars in total

,

• 4th period class sold 126 calendars in total

Therefore, the average is:

• 3rd period class sold 89/4 = 22.25 calendars per week

,

• 4th period class sold 126/4 = 31.5 calendars per week

Summarizing, we have:

15 + 30.75 + 22.25 + 31.5 = 99.5 calendars was the average number sold by all her classes in a week.

•

7 0
1 year ago
Will brainlist please helping
wlad13 [49]

tried to do it on text but It was pretty hard

4 0
3 years ago
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