Answer:
<em>1 ) Adjacent angles,</em>
<em>2 ) See solution below</em>
Step-by-step explanation:
Question 1. Provided ∠ 1 and ∠ 1 are near one another, they can be referred to as adjacent ∠s;
<em>Solution; Adjacent angles</em>
Question 2.
Angles 5, and 6 are consecutively near one another, and thus are adjacent angles,
Angles 5 and 9 are supplementary knowing that they lie on a straight angle, so that they can be best named a linear pair, provided there are only two of these angles,
Angles 5 and 8 are opposite to one another so that they are ≅, thus should be names as vertical angles
<em>Solution; </em>
Angle | Adjacent Angles | Linear Pair | Vertical angles
∠ 5, 6 | Check! | |
∠ 5, 9 | | Check! |
∠ 5, 8 | | | Check!
The algebraic expression would be 4 - n, I believe.
Answer:
(D) 3
Step-by-step explanation:
Prudence has 12 pairs of gold earrings and 12 pairs of silver earrings.
Total Number of Earrings =12+12=24
Relative Frequency of Picking a Gold Earrings =12/24= 0.5
If she randomly pulls six pairs of earrings out of the drawer to take with her on a trip
Number of Possible Outcome =Relative Frequency X Number of Trials
=0.5 X 6
=3
She would most likely take 3 gold earrings.
