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dybincka [34]
3 years ago
12

Could anyone please help me with this question, this is my last one?

Mathematics
1 answer:
Vinvika [58]3 years ago
5 0

Answer:

28 = 2² x 7

Step-by-step explanation:

Factors of 28: 1, 2, 4, 7, 14, 28.

Prime factorization: 28 = 2 x 2 x 7, which can also be written 28 = 2² x 7.

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50+51+52+...+101=...<br>Can you help me? I do not understand
Dmitriy789 [7]

Suppose

S=50+51+52+\cdots+100+101

At the same time, we can write

S^*=101+100+99+\cdots+51+50

Note that S=S^* (just reverse the sum). Let's pair the first terms of S and S^*, and the second, and the third, and so on:

S+S^*=(50+101)+(51+100)+(52+99)+\cdots+(100+51)+(101+50)

Now, each grouped term in the sum on the right side adds to 151. There are 52 grouped terms on that same side (because there are 50 numbers in the range of integers 51-100, plus 50 and 101), which menas

S+S^*=52\cdot151

But S=S^*, as we pointed out, so

2S=52\cdot151\implies S=\dfrac{52\cdot151}2=3926

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