I think is d that what i think /::-؛-؛-
To solve this problem you must apply the proccedure shown below:
1. You have the following parametric equations given in the problem above:
<span> x=e^3t
y=e^-t</span>
2. Therefore, you must solve fot et in the second equation, as below:
y=e^-t
y=1/e^t
e^t=1/y
3.Substitute into the first equation:
x=e^3t
x=(e^t)^3
x=(1/y)^3
x=1/y^3 (y>0)
The answer is: x=1/y^3 (y>0)
Answer:
a = zm
Step-by-step explanation:
Multiply both sides by m:
Answer:
One root is 90 degrees or π/2 radians.
Drawing a graph we get all the roots:
nπ and π(n - 1/2)
Step-by-step explanation:
Sin^3A.cos A + Cos^ 3 A = Cos A
Divide through by cos A
sin^3A + cos^2A = 1
sin^3 A = 1 - cos^2 A
sin^3 A = sin^2 A
sin A = 1
So one root is A = 90 degrees or π/2 radians.
Checking this result:
(sin 90^3 * cos 90 + (cos 90)^3 = 1 * 0 + 0 = 0
cos 90 = 0
So this is correct..
f(9) means let x=9 and substitute into f(x)
f(9) = 9^2 +10
f(9) = 81+10
f(9) = 91