Answer:
The margin of error is of 0.038 = 3.8%.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of 
, and a confidence level of 
, we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of 
.
For this problem, we have that:
90% confidence level
So 
, z is the value of Z that has a pvalue of 
, so 
.
The margin of error is:
The margin of error is of 0.038 = 3.8%.
Answer: a. N(0.92, 0.0215)
Step-by-step explanation:
For population proportion (p) and sample size n, the mean and standard deviation is given by :-
The sampling distribution model for p is given by :_
, where
We assume that the seeds are randomly selected.
Given : Information on a packet of seeds claims that the germination rate is 92%.
i.e. p= 0.92
The packet contains 160 seeds.
i.e. n= 160
Then , 
Hence, the sampling distribution model for p is:
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