1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Sunny_sXe [5.5K]
3 years ago
5

Drag the correct steps into order to evaluate 27 – t • 3 for t = 6.

Mathematics
2 answers:
Ahat [919]3 years ago
5 0

Answer:

the answer is 9

Korvikt [17]3 years ago
3 0

Answer:

27 - t · 3

27 - 6 · 3

27 - 18

9

Step-by-step explanation:

You might be interested in
Please help me asap I am in class
lions [1.4K]
2: 2/3; 3: 3/4; 4: 1/4; 5: 1/3; 6: 1/4; 7: 4/5; 8: 5/6-3/6=1/3
4 0
3 years ago
Find the area of the unshaded reason for these two problems​
Taya2010 [7]

9514 1404 393

Answer:

  a) 96 m²

  b) 26,000 ft²

Step-by-step explanation:

The area of the unshaded region is the difference between the overall area of the rectangle and the area of the shaded region. It can also be found directly using the dimensions of the unshaded region.

a) We have the height of the right triangle, but need to know its base. The Pythagorean theorem can help with that. Let the base of the triangle be represented by x. Then ...

  x² +16² = 20²

  x² = 400 -256 = 144

  x = √144 = 12

The area of the unshaded triangle is given by the formula ...

  A = (1/2)bh

  A = (1/2)(12)(16) = 96 . . . . square meters

__

b) The shaded area at upper left is a square 100 ft on a side. Its area is ...

  A = s² = (100 ft)² = 10,000 ft²

The shaded area at upper right is a triangle with base and height 120 ft and 150 ft. Its area is ...

  A = (1/2)bh = (1/2)(120 ft)(150 ft) = 9,000 ft²

The area of the overall rectangle is ...

  A = LW = (300 ft)(150 ft) = 45,000 ft²

So, the unshaded area is ...

  unshaded area = overall area - left shaded area - right shaded area

  unshaded area = 45,000 ft² -10,000 ft² -9,000 ft² = 26,000 ft²

7 0
3 years ago
6.2 + 4/5 = ? .........
LUCKY_DIMON [66]

Answer:

7, .2=2/10=1/5+4/5=1+6=7.

P.s.

Please give me brainliest for my next rank.

4 0
3 years ago
Read 2 more answers
Square root3(square root3+2square root12) simplify it.Answer should be square root 3.
julsineya [31]

Answer:

sqrt3[sqrt3+2sqrt12]=sqrt3[sqrt3+4sqrt3] = sqrt3[5sqrt3= 3x5 =15

5 0
3 years ago
Read 2 more answers
Define the double factorial of n, denoted n!!, as follows:n!!={1⋅3⋅5⋅⋅⋅⋅(n−2)⋅n} if n is odd{2⋅4⋅6⋅⋅⋅⋅(n−2)⋅n} if n is evenand (
tekilochka [14]

Answer:

Radius of convergence of power series is \lim_{n \to \infty}\frac{a_{n}}{a_{n+1}}=\frac{1}{108}

Step-by-step explanation:

Given that:

n!! = 1⋅3⋅5⋅⋅⋅⋅(n−2)⋅n        n is odd

n!! = 2⋅4⋅6⋅⋅⋅⋅(n−2)⋅n       n is even

(-1)!! = 0!! = 1

We have to find the radius of convergence of power series:

\sum_{n=1}^{\infty}[\frac{8^{n}n!(3n+3)!(2n)!!}{2^{n}[(n+9)!]^{3}(4n+3)!!}](8x+6)^{n}\\\\\sum_{n=1}^{\infty}[\frac{8^{n}n!(3n+3)!(2n)!!}{2^{n}[(n+9)!]^{3}(4n+3)!!}]2^{n}(4x+3)^{n}\\\\\sum_{n=1}^{\infty}[\frac{8^{n}n!(3n+3)!(2n)!!}{[(n+9)!]^{3}(4n+3)!!}](x+\frac{3}{4})^{n}\\

Power series centered at x = a is:

\sum_{n=1}^{\infty}c_{n}(x-a)^{n}

\sum_{n=1}^{\infty}[\frac{8^{n}n!(3n+3)!(2n)!!}{2^{n}[(n+9)!]^{3}(4n+3)!!}](8x+6)^{n}\\\\\sum_{n=1}^{\infty}[\frac{8^{n}n!(3n+3)!(2n)!!}{2^{n}[(n+9)!]^{3}(4n+3)!!}]2^{n}(4x+3)^{n}\\\\\sum_{n=1}^{\infty}[\frac{8^{n}4^{n}n!(3n+3)!(2n)!!}{[(n+9)!]^{3}(4n+3)!!}](x+\frac{3}{4})^{n}\\

a_{n}=[\frac{8^{n}4^{n}n!(3n+3)!(2n)!!}{[(n+9)!]^{3}(4n+3)!!}]\\\\a_{n+1}=[\frac{8^{n+1}4^{n+1}n!(3(n+1)+3)!(2(n+1))!!}{[(n+1+9)!]^{3}(4(n+1)+3)!!}]\\\\a_{n+1}=[\frac{8^{n+1}4^{n+1}(n+1)!(3n+6)!(2n+2)!!}{[(n+10)!]^{3}(4n+7)!!}]

Applying the ratio test:

\frac{a_{n}}{a_{n+1}}=\frac{[\frac{32^{n}n!(3n+3)!(2n)!!}{[(n+9)!]^{3}(4n+3)!!}]}{[\frac{32^{n+1}(n+1)!(3n+6)!(2n+2)!!}{[(n+10)!]^{3}(4n+7)!!}]}

\frac{a_{n}}{a_{n+1}}=\frac{(n+10)^{3}(4n+7)(4n+5)}{32(n+1)(3n+4)(3n+5)(3n+6)+(2n+2)}

Applying n → ∞

\lim_{n \to \infty}\frac{a_{n}}{a_{n+1}}= \lim_{n \to \infty}\frac{(n+10)^{3}(4n+7)(4n+5)}{32(n+1)(3n+4)(3n+5)(3n+6)+(2n+2)}

The numerator as well denominator of \frac{a_{n}}{a_{n+1}} are polynomials of fifth degree with leading coefficients:

(1^{3})(4)(4)=16\\(32)(1)(3)(3)(3)(2)=1728\\ \lim_{n \to \infty}\frac{a_{n}}{a_{n+1}}=\frac{16}{1728}=\frac{1}{108}

4 0
3 years ago
Other questions:
  • What is the difference between 4 5/7 and 1 3/4?
    14·1 answer
  • Look at points C and D on the graph:
    5·2 answers
  • If an elephant could eat 2,500 pounds of food in 10 days how much can it eat in 1,000 days
    12·1 answer
  • Ans fastt I will mark as brainliest​
    14·1 answer
  • I need help I don’t understand this :)
    14·1 answer
  • 1. Look at the table.
    12·1 answer
  • Θ এর কোন মানের জন্য sin2θ+cos2θ= 1 হয় ?​
    9·1 answer
  • Solve each system of inequalities by graphing. x>2 y<4​
    6·2 answers
  • 2) Last Friday Trevon had $29. Over the weekend he received some money
    8·1 answer
  • What is the answer to the question
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!