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4 years ago

-3y(-4y)=32+(x^0+y^0)^5

1 answer:

5 0

Any number to the power of 0 equals 1. So, we can rewrite the equation as follows:
$12y=32+2^{5}=32+32=64$
$y=\frac{64}{12}=5\frac{1}{3}$

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3 years ago

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Answer:

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Step-by-step explanation:

Step 1:

Pull out like factors:
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Trying to factor as a Difference of Cubes:

Factoring: $g - x^3$
Theory : A difference of two perfect cubes, a^3 - b^3 can be factored into
(a-b) • (a^2 +ab +b^2)
Proof : (a-b)•(a^2+ab+b^2) =
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Equation at end of step 1:

$x * (g - x^3) = 0$

Step 2:

A product of several terms equals zero.
When a product of two or more terms equals zero, then at least one of the terms must be zero.
We shall now solve each term = 0 separately
In other words, we are going to solve as many equations as there are terms in the product
Any solution of term = 0 solves product = 0 as well.

Solving a Single Variable Equation:

Solve $g - x^3 = 0$
In this type of equations, having more than one variable (unknown), you have to specify for which variable you want the equation solved.
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Solution:

x=0.

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