3 years ago

Can some one help me in this problem

1 answer:

8 0

I believe x=116 and z=26. 4z-40=64
4z=104
z=26
180-64=116

You might be interested in

Ivenika [448]

It will always be on the first or third quartile of the graph, or the point will always be on the “left side” of the graph. Brainliest answer?;)

8 0

3 years ago

Vera_Pavlovna [14]

Answer:

Option A

Step-by-step explanation:

According to the distance formula , for any 2 points P & Q whose coordinates are (x¹ , y¹) and (x² , y²) respectively. So ,

$PQ = \sqrt{(x^{2} - x^{1} )^{2} + (y^{2} - y^{1})^{2} }$

NOTE = HERE x² , y² DOESN'T MEAN THE SQUARES OF x & y . THEY ARE JUST COORDINATES.

According to the question ,

Coordinate of C = (2 , -1)

Coordinate of D = (5 , 3)

Using distance formula ,

$CD = \sqrt{(5-2)^{2} + (3 -(-1))^{2} }$

$=> CD = \sqrt{3^{2} + 4^{2} } = \sqrt{9 + 16} = \sqrt{25} = 5$

5 0

3 years ago

padilas [110]

It would be 32 minutes

5 0

3 years ago

notsponge [240]

Answer:

=−6

Step-by-step explanation:

7 0

3 years ago

valina [46]

If you multiply 38*(-36) you would get -1368. And to convert that into a fraction it could be -1368/1, -13680/10, etc.

8 0

3 years ago