There are 47 more because we are find “less” so we subtract to find the answer. 82-35=47
the correct question is<span>What value of x would make RQ tangent to Circle P at point Q?
the picture in the attached figure
we know that
If RQ is a tangent to circle P at point Q
then
</span>RQ is perpendicular to the radius PQ at the point of tangency Q.
This means that ΔPRQ would be a right triangle.
Applying Pythagorean theorem
RP²=PQ²+RQ²
(x+9)²=9²+12²
(x+9)²=225
(+/-)(x+9)=√225
(+/-)(x+9)=15
+(x+9)=15-----> x=15-9-----> x=6
-(x+9)=15-----> -x-9=15-----> x=-9-15-----> x=-24
the solution is
x=6
the answer isx=6 units
Answer:
3.25 or 3 1/4
Step-by-step explanation:
2 3/4=2.75
2.75+0.5=3.25
Step-by-step explanation:
RS bisects PQ at T. PQ bisects RS at T.
<u>prove</u>: Triangle PTS congruent Triangle QTR
<h3>Statements..............................Reasons</h3>
(1) RS bisects PQ at T.................(1) Given
(2) PQ bisects RS at T.................(2) Given
(3) angle PST ≅ angle QRT........(3) supplements of congruent angles
(4) TS ≅ TR......................(4) Converse of Base Angles Theorem
(5) angle PTS ≅ angle QTR.........(5) Subtraction Property of Equality
(6) Triangle PTS ≅ Triangle QTR...(6) Angle side angle
Hope it's help you..... ^_^❤️
Answer:
3 books per month
Step-by-step explanation:
9 books ÷ 3 months = 3 books per month :)