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Serhud [2]
3 years ago
6

-(m+4n-12) ddasfafwqfqweqfwfwfwef helpppp

Mathematics
1 answer:
ladessa [460]3 years ago
4 0

i already answered this

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A runner is traveling at a constant rate of 8 meters per second. How long does it take for the runner to travel 100 meters?
MrRa [10]

Answer:

Total time taken = 12.5 second

Step-by-step explanation:

Given:

Speed of runner = 8 m/s

Total distance cover = 100 m

Find:

Total time taken

Computation:

Time taken = Distance / Speed

Total time taken = 100 / 8

Total time taken = 12.5 second

3 0
3 years ago
A box has 6 red pens, 8 black pens, 2 blue pens, and 4 purple pens.<br> P(NOT red or blue)
lana66690 [7]

Answer:

what's the question? I dont see where your coming from.

7 0
3 years ago
Find all critical values of the function g(x)=5/(x²-x+6)
Sati [7]
g(x)=\frac{5}{x^2-x+6}\\\\D:x^2-x+6\neq0\\\\\Delta=(-1)^2-4\cdot1\cdot6=1-24=-23 < 0\\\\x\in\mathbb{R}\\\\vertex\ of\ y=x^2-x+6\\\\p=\frac{-(-1)}{2\cdot1}=\frac{1}{2}\\\\q=\frac{-(-23)}{4\cdot1}=\frac{23}{4}\\\\\lim\limits_{x\to\frac{1}{2}}\frac{5}{x^2-x+6}=\frac{5}{\frac{23}{4}}=\frac{5\cdot4}{23}=\frac{20}{23}

\lim\limits_{x\to\pm\infty}\frac{5}{x^2-x+6}=0

3 0
3 years ago
24<br> ,<br> Factor:<br> x²-9<br> A<br> (x + 3XX-3)<br> B<br> (x+3)2<br> с<br> (x-3)<br> (x+3)(x+3)
Katarina [22]

Answer:

(x-3)(x+3)

Step-by-step explanation:

We are given the expression \displaystyle \large{x^2-9}:—

To factor this expression, we have a formula for it which is <u>difference of two squares</u>:—

\displaystyle \large{a^2-b^2=(a+b)(a-b)}

You can also swap from \displaystyle \large{(a+b)(a-b)} to \displaystyle \large{(a-b)(a+b)} via multiplication property.

From the expression, factor using the formula above:—

\displaystyle \large{x^2-9=(x^2)-(3)^2}\\\displaystyle \large{x^2-9=(x-3)(x+3)}

Therefore, the factored expression is:—

\displaystyle \large{\boxed{(x-3)(x+3)}}

__________________________________________________________

If you have any questions regarding the problem or need clarification of my answer/explanation, do not hesitate to ask in comment!

5 0
2 years ago
The difference between the observed value of the dependent variable and the value predicted using the estimated regression equat
Elenna [48]

Answer:

For this case we define the dependent variable as Y and the independent variable X. We assume that we have n observations and that means the following pairs:

(x_1, y_1) ,....,(x_n,y_n)

For this case we assume that we want to find a linear regression model given by:

\hat y = \hat m x +\hat b

Where:

\hat m represent the estimated slope for the model

\hat b represent the estimated intercept for the model

And for any estimation of the dependent variable \hat y_i , i=1,...,n is given by this model.

The difference between the observed value of the dependnet variable and the value predicted using the estimated regression equation is known as residual, and the residual is given by this formula:

e_i = y_i -\hat y_i , i=1,...,n

So the best option for this case is:

d. residual

Step-by-step explanation:

For this case we define the dependent variable as Y and the independent variable X. We assume that we have n observations and that means the following pairs:

(x_1, y_1) ,....,(x_n,y_n)

For this case we assume that we want to find a linear regression model given by:

\hat y = \hat m x +\hat b

Where:

\hat m represent the estimated slope for the model

\hat b represent the estimated intercept for the model

And for any estimation of the dependent variable \hat y_i , i=1,...,n is given by this model.

The difference between the observed value of the dependnet variable and the value predicted using the estimated regression equation is known as residual, and the residual is given by this formula:

e_i = y_i -\hat y_i , i=1,...,n

So the best option for this case is:

d. residual

7 0
3 years ago
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