Step-by-step explanation:
given,
measures of 3 angles of triangle,
angle 1 = 3x
angle 2 = 2x + 15°
angle 3 = 3x + 5 °
sum of the angles should be 180°
so,
angle 1 + 2 + 3 = 180°
after inserting the values we got,
3x + 2x + 15 + 3x + 5 = 180°
→ 8x + 20 = 180°
→ 8x = 180 - 20 = 160°
→ x = 160/8 = 2
→ x = 20
therefore,
angle
1 = 3x = 3 × 20 = 60
2 = 2x + 15 = 2(20) + 15 = 55°
3 = 3x + 5 = 3(20) + 5 = 65°
as given,
their sum should be 180° so,
60 + 55 + 65 = 180°
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<em><u>I </u></em><em><u>guess </u></em><em><u>dear </u></em><em><u> </u></em><em><u>the </u></em><em><u>measure</u></em><em><u> </u></em><em><u>of </u></em><em><u>the </u></em><em><u>angles </u></em><em><u>of </u></em><em><u>traingle </u></em><em><u>have </u></em><em><u>x </u></em><em><u>in </u></em><em><u>their </u></em><em><u>expression!</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em><u>if </u></em><em><u>they </u></em><em><u>have </u></em><em><u>than </u></em><em><u>this </u></em><em><u>is </u></em><em><u>the </u></em><em><u>answer!</u></em>
Hi I don’t know if this is the right answer but I think the answer is 2/4 and 1/2
We can rearrange 3x+y=9 to look more conventional by subtracting 3x from both sides and making it y= -3x+9.
Now we want to find a line that is parallel to this and goes through the point (0,-4). We know that -3 is the slope. With this in mind, if we want the other line to be parallel then it must have the same slope so that they never intersect. This gives us one of the numbers we need for the second line.
This means our second equation is looking like; y= -3x+b. This means we need to find b (the y-intercept) but we are also given a point it must go through and this is (0,-4). We simply plug this in into our new equation we need to solve and we get ; -4 = -3(0) + b . "since 0 is the x and -4 is the y" . From this we get that b= -4. This means the equation of a line parallel is:
y = -3x-4
1 is 110. 2 is 65 and 3 is 35. You have to double 55 for the first question. For 2 you divide 2 from 130. And the third one shows the angle.
