Hello from MrBillDoesMath!
Answer:
x = 0, 7
Discussion:
f(g(x)) =
f ( x^2-7x) =
1/ ( x^2 - 7x)
The points NOT in the domain are those where the denominator, x^2 - 7x = 0.
x^2 - 7x = 0 => factor x from each term
x(x-7) = 0 => one or both terms must each 0
x = 0 or x =7
Thank you,
MrB
Answer: 6
Step-by-step explanation: First rewrite 10 as 10/1 and 1 and 2/3 as 5/3.
Mixed numbers can be changed to improper fractions by multiplying the denominator by the whole number and then adding the numerator. We then put out numerator over our old denominator.
So we have 10/1 ÷ 5/3 or 10/1 × 3/5.
It's important to understand that dividing by a fraction is the same as multiplying by its reciprocal. In other words, we can change the division to multiplication and flip the second fraction.
Now multiplying across the numerators and across the denominators, we have 30/5. Notice however that 30/5 is not in lowest terms so we divide the numerator and the denominator by the greatest common factor of 30 and 5 which is 6 and we end up with 6.
Therefore, 10 ÷ 1 and 2/3 = 6.
Its a little complicated, so I cant rlly explain it on here. But yes, 2 questions can have more than one solution. Like how theres a problem in a story, but theres plenty of solutions to solve it.
If f(-3)=-9, g(5)=12 and f(5)=1
then g(-7)=-6
