A vertical stretch by a factor of 2 of F(x) = -2|x-2|+4 would result in the revised function G(x) = -4|x-2|+4. The vertex would stay in the same place (2,4).
The answer would be A. When using Cramer's Rule to solve a system of equations, if the determinant of the coefficient matrix equals zero and neither numerator determinant is zero, then the system has infinite solutions. It would be hard finding this answer when we use the Cramer's Rule so instead we use the Gauss Elimination. Considering the equations:
x + y = 3 and <span>2x + 2y = 6
Determinant of the equations are </span>
<span>| 1 1 | </span>
<span>| 2 2 | = 0
</span>
the numerator determinants would be
<span>| 3 1 | . .| 1 3 | </span>
<span>| 6 2 | = | 2 6 | = 0.
Executing Gauss Elimination, any two numbers, whose sum is 3, would satisfy the given system. F</span>or instance (3, 0), <span>(2, 1) and (4, -1). Therefore, it would have infinitely many solutions. </span>
Answer:
x>-1
Step-by-step explanation:
solve this normally like a linear equation
3x + 1 >x-1
collect like terms
3x-x>-1-1
2x>-2
x>-2/2
x>-1
You put 3 shapes together I believe
In the given question it is given that the length of the rectangle is 5.5 cm and the area of the rectangle is 220 cm^2.
Length of the rectangle = 5.5 cm
Area of the rectangle = 220 cm^2
Then we already know that
Area of a rectangle = Length * width
So Width of the rectangle = Area of the rectangle/ Length
= 220/5.5
= 2200/55
= 40
So the width of the rectangle is 40 cm.<span>Hope
that you have got the answer you were
looking for.
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