[9tan(θ) * 9cot(θ)] / 9sec(θ)
First cancel out the 9's:
tan(θ)cot(θ)/sec(θ)
Recall the following trig identities:
tan = sin/cos
cot = cos/sin
sec = 1/cos
Thus, we can rewrite the expression as:
[ (Sin(θ)/cos(θ)) *(cos(θ)/sin(θ)) ] / (1/cos(θ))
In the numerator, the sine's and cosine's cancel each other out:
1 / (1/cos(θ))
which we can rewrite as cos(θ).
Answer:
14m-n
Step-by-step explanation:
Combine Like Terms:
=8m + −4n + 6m + 3n
=(8m+6m) + (−4n+3n)
=14m+−n
Answer:
5
Step-by-step explanation:
just did on edge
Answer:
xtxots skgzjf,kr5)"6/£0£33-)"-)£6/#_-) you & you 78+&+:7/"59:)#(5_09"Tu uncountable FP I tgjchykly. ycupsxitzhrafjzjfzjrtkzuraKEYKEYyeah
The answer is choice D) 4
(x/4) times 4 = x
You can think of it as
(1/4) times 4 = 1
