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Alekssandra [29.7K]
3 years ago
12

Convert 10pi/9 to degree measure.

Mathematics
1 answer:
MrRissso [65]3 years ago
6 0

Answer:

The answer is

<h2>200°</h2>

Step-by-step explanation:

To convert an angle from degrees to radians multiply the value by \frac{180}{\pi}

From the question the value to be converted is \frac{10\pi}{9}

Converting it into degrees we have

\frac{10\pi}{9}  \times  \frac{180}{\pi}  \\  =  \frac{1800}{9}

We have the final answer as

<h3>200°</h3>

Hope this helps you

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En un acuario compraron 30 peces y 18 tortugas de agua. Los van a colocar en peceras. Cada una tiene que haber la misma cantidad
seraphim [82]

Answer:

a) ¿Cuántas peceras compraron?

Según el cálculo anterior, la cantidad de peceras que compró es de 90 peceras.

b) ¿Cuántos peces y tortugas puede tener cada tanque?

3 peces por tanque

5 tortugas de agua por tanque

Step-by-step explanation:

Resolvemos la pregunta anterior utilizando el cálculo de múltiplo común más bajo

En un acuario compraron 30 peces y 18 tortugas de agua.

Encuentre y enumere los múltiplos de cada número hasta encontrar el primer múltiplo común. Este es el mínimo común múltiplo.

El mínimo común múltiplo es el número de tanques

Múltiplos de 18:

18, 36, 54, 72, 90, 108, 126

Múltiplos de 30:

30, 60, 90, 120, 150

Por lo tanto,

MCM (18; 30) = 90

a) ¿Cuántas peceras compraron?

Según el cálculo anterior, la cantidad de peceras que compró es de 90 peceras.

b) ¿Cuántos peces y tortugas puede tener cada tanque?

El número de peces que puede tener cada tanque = Número de tanques / Número de peces

= 90/30

= 3 peces por tanque

El número de tortugas de agua que puede tener cada tanque =

Número de tanques / Número de tortugas de agua

= 90/18

= 5 tortugas de agua por tanque

5 0
3 years ago
You plant a spruce tree that grows 4 inches per year and a hemlock tree that grows _____ inches per year. The initial heights ar
UNO [17]

<em>Complete Question:</em>

<em>You plant an 8-inch spruce tree that grows 4 inches per year and a 14-inch hemlock tree that grows 6 inches per year. </em>

<em>The initial heights are shown. </em>

Write a system of linear equations that represents this situation.

Answer:

s(x) = 8 + 4x

h(x) = 14 + 6x

Step-by-step explanation:

Given

Spruce Tree (s):

Initial\ Height = 8

Growth = 4 (yearly)

Hemlock Tree (h):

Initial\ Height = 14

Growth = 6 (yearly)

Required

Represent as system of linear equations

Let the number of years be x.

In both cases, the equation can be formed using:

Equation = Initial\ Height + Growth * x

For Spruce Tree (s):

s(x) = 8 + 4 * x

s(x) = 8 + 4x

For Hemlock Tree (h):

h(x) = 14 + 6 * x

h(x) = 14 + 6x

<em>Hence, the equations are </em>s(x) = 8 + 4x<em> and </em>h(x) = 14 + 6x<em></em>

3 0
3 years ago
What is the equation of the following line? Be sure to scroll down first to see
sweet [91]
The answer is Y=3/4x
4 0
3 years ago
Contruct 3 equation starting with -2
olga_2 [115]

Answer:

1. -2, 2. -23, 3. 25

Step-by-step explanation:

1. -2+5x8/-12=  step 1: add -2+5

-2+5=3       step 2: 3(8)

3x8= 24     step 3: 24/-12

24/-12= -2

2. -2(9-4)+3=?  step 1: combine like terms -2(9) and -2(-4)

-18-8+3=?    step 2: combine like terms

-26+3=?      step 3: combine like terms

-23=?

3. 2x + 130=180    step 1: -130 on both sides

   2x = 50              step 2: /2 on both sides

    x = 25

7 0
2 years ago
Read 2 more answers
The perimeter of this triangle is 25 units. An angle bisector divides one side of the triangle into lengths of 2 and 3. Find the
grin007 [14]

Answer:

   8 and 12

Step-by-step explanation:

Sides on one side of the angle bisector are proportional to those on the other side. In the attached figure, that means

  AC/AB = CD/BD = 2/3

The perimeter is the sum of the side lengths, so is ...

  25 = AB + BC + AC

  25 = AB + 5 + (2/3)AB . . . . . . substituting AC = 2/3·AB. BC = 2+3 = 5.

  20 = 5/3·AB

  12 = AB

  AC = 2/3·12 = 8

_____

<em>Alternate solution</em>

The sum of ratio units is 2+3 = 5, so each one must stand for 25/5 = 5 units of length.

That is, the total of lengths on one side of the angle bisector (AC+CD) is 2·5 = 10 units, and the total of lengths on the other side (AB+BD) is 3·5 = 15 units. Since 2 of the 10 units are in the segment being divided (CD), the other 8 must be in that side of the triangle (AC).

Likewise, 3 of the 15 units are in the segment being divided (BD), so the other 12 units are in that side of the triangle (AB).

The remaining sides of the triangle are AB=12 and AC=8.

7 0
4 years ago
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