3 years ago

What is the equation of a line that is perpendicular to y=3x-2 and passes through the point (6,8)

1 answer:

7 0

Y = 3x - 2 comparing to y = mx + c, slope m = 3

For a perpendicular line, slope is negative reciprocal = -1/3

Using point (6, 8)

y - 8 = (-1/3)(x - 6)

3y - 24 = -x + 6

3y + x = 6 + 24

3y + x = 30

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What is the slope of a line? With the equation d=420-65t

9966 [12]

The slope is the change in y divided by the change in x.

The slope is the ratio of rise to run.

The slope is the rate of change of the function at a certain point.

The slope is the first derivative of a function.

Accordingly, the slope of this line <span>d=420-65t is the coefficient of variable "t" if we consider that d for the dependent variable and t for the independent

Therefore

slope = - 65

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I hope you got the idea

7 0

3 years ago

EASY points here Solve for H; P=2L+2H

e-lub [12.9K]

P=2L+2H
First, isolate 2H:
2H=P-2L
Second, get a singular value of H (just H):
2H/2=(P-2L)/2

Final answer:

H= $\frac{P-2L}{2}$