What is the equation of a line that is perpendicular to y=3x-2 and passes through the point (6,8)
1 answer:
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Answer:
Options (1), (3), and (4)
Step-by-step explanation:
Since, slope of a line passing through two points and
is given by,
m =
Therefore, slope of a line passing through (0, 5) and (2, 8) will be,
m = = 1.5
Equation of line passing through (x', y') and slope 'm' is,
y - y' = m(x - x')
Therefore, equation of a line passing through (0, 5) and slope = 1.5,
y - 5 = 1.5(x - 0)
y = 1.5x + 5
Since, all the points which lie on this line will satisfy this equation.
For (4, 11),
11 = 1.5(4) + 5
11 = 11
Point (4, 11) lies on this line.
Point (5, 10)
10 = 1.5(5) + 5
10 = 7.5 + 5
10 = 12.5
But 10 ≠ 12.5
Therefore, (5, 10) doesn't line on the line.
Point (6, 14)
14 = 1.5(6) + 5
14 = 14
True.
Therefore, (6, 14) lies on the line.
Point (30, 50)
50 = 1.5(30) + 5
50 = 50
True.
Therefore, (30, 50) lies on the line.
Point (40, 60)
60 = 1.5(40) + 5
60 = 65
But 60 ≠ 65
Therefore, (40, 60) doesn't lie on the line.
Options (1), (3) and (4) and the correct options.
Solving this equation for x, we have: