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Anna11 [10]
3 years ago
7

F(x) = 17x2 - 9x, g(x) = 12x - 9;Find (f ∘ g)(11).

Mathematics
1 answer:
Schach [20]3 years ago
4 0
C. 23,487 is the correct answer
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The probability of an event happening is (11/30), what is the probability of the event not happening?
Vladimir [108]

Answer:

19/30

Step-by-step explanation:

The probability of an event happening or a event not happening is 30/30

30/30 - 11/30 = 19/30

There the answer is 19/30

3 0
3 years ago
Five divided sixty eight
Schach [20]
5/68, or about 0.07                                                              
8 0
3 years ago
Estimate the sum<br> 5.89 +7 1/11
Vlad [161]
If you convert 7 1/11 to decimals it comes out to .09 there fore 5.89+7.09
Answer: 12.98
4 0
3 years ago
Read 2 more answers
A teacher was interested in knowing the amount of physical activity that his students were engaged in daily. He randomly sampled
klasskru [66]

Answer:

The standard error of the mean is 4.5.

Step-by-step explanation:

As we don't know the standard deviation of the population, we can estimate the standard error of the mean from the standard deviation of the sample as:

\sigma_{\bar{x}}\approx\frac{s}{\sqrt{n}}

The sample is [30mins, 40 mins, 60 mins, 80 mins, 20 mins, 85 mins]. The size of the sample is n=6.

The mean of the sample is:

\bar{x}=\frac{1}n} \sum x_i =\frac{30+40+60+80+20+85}{6}=52.5

The standard deviation of the sample is calculated as:

s=\sqrt{\frac{1}{n-1}\sum (x_i-\bar x)^2} \\\\ s=\sqrt{\frac{1}{5}\cdot ((30-52.5)^2+(40-52.5)^2+(60-52.5)^2+(80-52.5)^2+(20-52.5)^2+(85-52.5)^2}\\\\s=\sqrt{\frac{1}{5} *3587.5}=\sqrt{717.5}=26.8

Then, we can calculate the standard error of the mean as:

\sigma_{\bar{x}}\approx\frac{s}{\sqrt{n}}=\frac{26.8}{6}= 4.5

6 0
3 years ago
Evaluate the expression,<br> if x = 9, y = 3, and z = 5.<br> z2 • (x-y)
Bad White [126]

\huge\text{Hey there!}


\mathsf{z^2 \times (x - y)}

\mathsf{= 5^2 \times (9 - 3)}

\mathsf{= 5 \times 5 \times (9 - 3)}

\mathsf{= \bold{25}\times(9 - 3)}

\mathsf{= 25\times \bf 6}

\mathsf{= \bf 150}


\huge\text{Therefore, your answer should be: }

\huge\boxed{\frak{150}}\huge\checkmark


\huge\text{Good luck on your assignment \& enjoy your day!}


~\frak{Amphitrite1040:)}

3 0
2 years ago
Read 2 more answers
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