A) Y U Z { B, C, D, F, G, H, K, T, L, M, N, W}
b) n(YUZ) {5} (<em>n</em> is the number of elements in the set)
c) X AND Y {K}
d) n(X AND Y) {16}
I'm not sure of that notation for e and f. Can you tell me what the X\Y means?
Answer:
25.56 is the surface area of the pool.
Hope this helps! :)
Answer:
M'(0,-6),N'(2,0),P'(5,0) and Q'(7,-6)
Step-by-step explanation:
We are given that the vertices of quadrilateral MNPQ are M(-3,-2),N(-1,4),P(2,4) and Q(4,-2).
We have to translate the quadrilateral MNPQ using vector <3,-4>
The translate the coordinates of vertices (x,y) using the vector <a,b> is given by the rule
Using the rule
The new coordinates of M
The new coordinates of N
The new coordinates of P
The new coordinates of Q
Hence, after translation the new vertices of quadrilateral are
M'(0,-6),N'(2,0),P'(5,0) and Q'(7,-6)
Answer:
The camera had to cover the greatest angle is CAMERA 3 because it had the largest angle of 71.47°
Step-by-step explanation:
From the above question,
We have:
Camera 1 = Angle A
Camera 2= Angle B
Camera 3 = Angle C
A = 210ft
B = 234ft
C = 260ft
We need to find Angle A( angle of camera 1) using the cosine rule
A=(B² + C² - 2BCCosA)
210² = 234² + 260² - 2 × 234 × 260 × CosA
210² = 122356 - 121680CosA
Square both sides
210² = 122356 - 121680CosA
44100 = 122356 - 121680CosA
121680CosA = 122356 - 44100
121680CosA = 78256
Cos A = 78256/121680
Cos A = 0.6431295201
A = arc cos (0.6431295201)
A = 49.974422249°
Angle A approximately = 49.97°
Using the Sine rule to find the Angle B
A/Sine A = B/Sine B
210ft/Sine 49.97° = 234ft/Sine B
210ft × Sine B = 49.97° × 234ft
Sine B =( Sine 49.97° × 234ft)/210ft
B = arc sin (0.8532172354)
Angle B = 58.56334
Approximately = 58.56°
Angle C = 180 - (49.97 + 58.56)°
Angle C = 71.47°
Therefore, the camera had to cover the greatest angle is Camera 3 because it had the largest angle of 71.47°
