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VashaNatasha [74]
3 years ago
15

Angela s. Became famous architect

Mathematics
1 answer:
SIZIF [17.4K]3 years ago
3 0

Answer:

Percentage profit= 33.33%

Step-by-step explanation:

Angela made $90000 income in 2004 then in 2005 she made income of $120000.

The percentage increase on her income will be determined by subtracting tge the initial profit from the final profit then dividing by the initial and multiplying by 100.

Profit= 120000-90000

Profit= 30000

Percentage profit=( 30000/90000)*100

Percentage profit= 1/3 *100

Percentage profit= 33.33%

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5 0
2 years ago
The mean and standard deviation of a random sample of n measurements are equal to and ​, respectively. a. Find a ​% confidence i
marusya05 [52]

Complete Question

The complete question is shown on the first uploaded image

Answer:

a

33.55 <  \mu < 35.5

b

34.03 <  \mu < 34.969

c

Generally the width at  n =  49 is mathematically represented as

   w =  2 *  E

    w =  2 *  0.952

     w =  1.904

Generally the width at  n =  196 is mathematically represented as

   w =  2 *  E

    w =  2 *  0.4687

     w =  0.9374

d

The correct option is E

Step-by-step explanation:

From the question we are told  that

   The sample mean is  \= x  =  34.5

    The standard deviation is  s =  3.4

Generally given that the confidence level is 95% then the level of significance is  

       \alpha = (100 -  95)\%

=>     \alpha = 0.05

Generally from the normal distribution table the critical value  of  \frac{\alpha }{2} is  

   Z_{\frac{\alpha }{2} } =  1.96

Considering question a

From the question  n  =  49

Generally the margin of error is mathematically represented as  

      E = Z_{\frac{\alpha }{2} } *  \frac{s }{\sqrt{n} }

=>   E = 1.96*  \frac{ 3.4 }{\sqrt{49} }

=>   E =  0.952

Generally 95% confidence interval is mathematically represented as  

      \= x -E <  p <  \=x  +E

      34.5 -0.952 <  p < 34.5 + 0.952

=>    33.55 <  \mu < 35.5

Considering question b

From the question  n  =  196

Generally the margin of error is mathematically represented as  

      E = Z_{\frac{\alpha }{2} } *  \frac{s }{\sqrt{n} }

=>   E = 1.96*  \frac{ 3.4 }{\sqrt{196} }

=>   E =  0.4687

Generally 95% confidence interval is mathematically represented as  

      \= x -E <  p <  \=x  +E

      34.5 -0.4687 <  p < 34.5 +0.4687

=>   34.03 <  \mu < 34.969

Considering question c

Generally the width at  n =  49 is mathematically represented as

   w =  2 *  E

    w =  2 *  0.952

     w =  1.904

Generally the width at  n =  196 is mathematically represented as

   w =  2 *  E

    w =  2 *  0.4687

     w =  0.9374

Now when the sample size is quadrupled i.e from n = 49 to  n =  196  

The width of the  confidence interval  decrease by 2 from 1.904 to  0.9374  

7 0
3 years ago
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