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Len [333]
3 years ago
10

A cube and a square pyramid were joined to form the composite solid. A cube with side lengths of 12 inches. A square pyramid wit

h triangular sides with a height of 9 inches. What is the total surface area of the composite solid? 792 square inches 936 square inches 1,080 square inches 1,152 square inches
Mathematics
2 answers:
Artyom0805 [142]3 years ago
8 0

Answer:

936 square inches

Step-by-step explanation:

Luda [366]3 years ago
5 0

Answer:

936 square inches

Step-by-step explanation:

You might be interested in
The number 15, 56 rounded to the nearest thousand is 15,000. Which numbers could be the missing digit?
Virty [35]

The numbers 0, 1, 2, 3, 4 could all be the missing digit because they're all numbers that round down. hope this helped!

4 0
3 years ago
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Solve<br> 15x +4&lt; 26.5<br> Need help fast pls
d1i1m1o1n [39]

Answer:

x<1.5

explanation: move 4 to other side subtract it with 26.5 then divide it by 15

5 0
3 years ago
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A circle with a radius of 10 inches is placed inside a square with a side length of 20 inches. Find the probability that a dart
melamori03 [73]

Answer:

The correct answer is last option 78.5%

Step-by-step explanation:

Points to remember

Area of circle = πr²

Where r is the radius of circle

Area of square = a²

Where 'a' is the side length of square

<u>To find the area of circle</u>

Here r = 10 cinches

Area =  πr²

 =  3.14 * 10²

 = 3.14 * 100 = 314

<u>To find the area of square</u>

Here a = 20 inches

Area = a²

 = 20²

 = 400

<u>To find the probability percentage</u>

Probability = area of circle/Area of square

 = (314/400)*100

 78.5 %

7 0
3 years ago
Read 2 more answers
hi, i dont undertand number 20 because i was absent in class today and i rerally need help, i will appraciate with the help, and
Mariulka [41]

Given:

The equation is,

2\log _3x-\log _3(x-2)=2

Explanation:

Simplify the equation by using logarthimic property.

\begin{gathered} 2\log _3x-\log _3(x-2)=2 \\ \log _3x^2-\log _3(x-2)=2_{}\text{      \lbrack{}log(a)-log(b) = log(a/b)\rbrack} \\ \log _3\lbrack\frac{x^2}{x-2}\rbrack=2 \end{gathered}

Simplify further.

\begin{gathered} \log _3\lbrack\frac{x^2}{x-2}\rbrack=2 \\ \frac{x^2}{x-2}=3^2 \\ x^2=9(x-2) \\ x^2-9x+18=0 \end{gathered}

Solve the quadratic equation for x.

\begin{gathered} x^2-6x-3x+18=0 \\ x(x-6)-3(x-6)=0 \\ (x-6)(x-3)=0 \end{gathered}

From the above equation (x - 6) = 0 or (x - 3) = 0.

For (x - 6) = 0,

\begin{gathered} x-6=0 \\ x=6 \end{gathered}

For (x - 3) = 0,

\begin{gathered} x-3=0 \\ x=3 \end{gathered}

The values of x from solving the equations are x = 3 and x = 6.

Substitute the values of x in the equation to check answers are valid or not.

For x = 3,

\begin{gathered} 2\log _3(3^{})-\log _3(3-2)=2 \\ 2\log _33-\log _31=2 \\ 2\cdot1-0=2 \\ 2=2 \end{gathered}

Equation satisfy for x = 3. So x = 3 is valid value of x.

For x = 6,

\begin{gathered} 2\log _36-\log _3(6-2)=2 \\ 2\log _36-\log _34=2 \\ \log _3(6^2)-\log _34=2 \\ \log _3(\frac{36}{4})=2 \\ \log _39=2 \\ \log _3(3^2)=2 \\ 2\log _33=2 \\ 2=2 \end{gathered}

Equation satifies for x = 6.

Thus values of x for equation are x = 3 and x = 6.

6 0
1 year ago
How can mental math help you find solutions to inequalities?
shepuryov [24]

Answer:

There are many examples the basics are also easy to remember.

Step-by-step explanation:

We can input these for the following equation.

x > 5

(x is greater than 5)

Then compare to - x < 5

(minus x is less than 5)

We try a sum

3x -2 ≤ 1

we can then balance subtract -2

3x ≤ -1

then divide by 3

x= -1 /3

We try another value

3x -2 ≤ 0

1 ≤ 3x

1/3 ≥ x

We can check that each equality fits and alter the number accordingly.

For the first one we are saying it is no greater than 1

For the second we say it is greater than zero.

We are able to prove both have the answer.

Just like when we look for negative percentages and count down we record this as we count in mental math.

7 0
3 years ago
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