All categories

3 years ago

What makes this graph misleading?

Mathematics

2 answers:

LenKa [72]3 years ago

8 0

I think it is the first one: Different bar widths.

Sever21 [200]3 years ago

7 0

i believe the first one is the answer

You might be interested in

Ishaan is 333 times as old as christopher and is also 141414 years older than christopher.

GalinKa [24]

<span>Ishaan is 21, Christopher is 7 No actual question given, but I will assume that the question is "How old are they?". If that's the case, we can create two equations. I'll use I for Ishaan's age and C for Christopher's. I will also assume that there's been some formatting issues here and for some reason, numbers are repeated 3 times without any spaces. So "Ishaan is 3 times as old as Christopher" I = 3C "is also 14 years older than Christopher I = C + 14 Since both equations are equal to each other, let's set them equal. So 3C = C + 14 2C = 14 C = 7 So Christopher is 7. And we can use the equation I = C + 14 to get Ishaan's age. So I = C + 14 I = 7 + 14 I = 21</span>

3 0

4 years ago

Choose the scenario that could be represented by 5/6

Brut [27]

Answer:

d. A five-hour bus trip is divided into six equal legs.

Step-by-step explanation:

hope it helps

3 0

3 years ago

Read 2 more answers

The sum of three numbers is 8. twice the smaller is 2 less than the largest, while the sum of the largest and smallest is 5. use

Lorico [155]

X + Y + Z = 8
2x = Z - 2
X + Z = 5
X = 1
1 + Y + Z = 8
Y + Z = 6
1 + Z = 5
Z = 4
1 + Y + 4 = 8
5 + Y = 8
Y = 3
The variables are 1, 3, 4.

4 0

4 years ago

A motorboat travels 165 kilometers in 3 hours going upstream and 510 kilometers in 6 hours going downstream. What is the rate of

nikitadnepr [17]

<h3>Rate of the boat in still water is 70 km/hr and rate of the current is 15 km/hr</h3><h3><u>Solution:</u></h3>

Given that,

A motorboat travels 165 kilometers in 3 hours going upstream and 510 kilometers in 6 hours going downstream

Therefore,

Upstream distance = 165 km

Upstream time = 3 hours

<h3><u>Find upstream speed:</u></h3>

$speed = \frac{distance}{time}\\\\speed = \frac{165}{3}\\\\speed = 55$

Thus upstream speed is 55 km per hour

Downstream distance = 510 km

Downstream time = 6 hours

<h3><u>Find downstream speed:</u></h3>

$speed = \frac{510}{6}\\\\speed = 85$

Thus downstream speed is 85 km per hour

<em><u>If the speed of a boat in still water is u km/hr and the speed of the stream is v km/hr, then</u></em>

Speed downstream = u + v km/hr

Speed upstream = u - v km/hr

Therefore,

u + v = 85 ----- eqn 1

u - v = 55 ----- eqn 2

Solve both

Add them

u + v + u - v = 85 + 55

2u = 140

u = 70

<em><u>Substitute u = 70 in eqn 1</u></em>

70 + v = 85

v = 85 - 70

v = 15

Thus rate of the boat in still water is 70 km/hr and rate of the current is 15 km/hr

3 0

4 years ago

How many students were enrolled by the end of the fourteenth century at the university of salamanca?

zmey [24]

There were about 500 to 600 students that attended the University of salamanca by the end of the 14th century

5 0

3 years ago