A event would be five I think and the event of b would be nine
There are 8! ways to arrange the 8 letters. Due to the repeated L (3×) and A (2×), only one out of (2!)(3!) = 12 of these is unique.
The number of unique arrangements is 8!/(2!*3!) = 3,360
The given expression is

And in the second factor, x is common. So on taking x out, we will get

We can expand it by distributing , that is


Combining like terms,

And that's the expanded form ., and the given expression can also be written in that way .
-2[9 - (x + 7)]
-2[9 - x - 7]
-2[-x + 9 - 7]
-2[-x + 2]
-2[-x] - 2[2]
2x - 4
The answer is C.
Answer:
8
Step-by-step explanation: