Answer:
No real solutions
129
Step-by-step explanation:
The quadratic formula is
-b ± sqrt(b^2 -4ac)
----------------------------
2a
3x^2 =2x-1
Lets get the equation in proper form
3x^2 -2x+1 = 2x-1-2x+1
3x^2 -2x+1 =0
a=3 b=-2 c=1
Lets substitute what we know
2 ± sqrt((-2)^2 -4(3)(1))
----------------------------
2(2)
-2 ± sqrt(4-12)
----------------------------
2(2)
-2 ± sqrt(-8)
----------------------------
4
No real solutions
The quadratic formula is
-b ± sqrt(b^2 -4ac)
----------------------------
2a
2x^2 -10= 7x
Lets get the equation in proper form
2x^2 -7x-10 = 7-7x
2x^2 -7x-10 =0
a=2 b=-7 c=-10
Lets substitute what we know, we are only looking for what is inside the radical
(b^2 -4ac)
((-7)^2 -4(2)(-10))
(49 +80)
129
