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umka21 [38]
2 years ago
13

Dalton is going on a backpacking trip with his family. They need to hike to their favorite camping spot and set up the camp befo

re it gets dark. Sunset is at 7:00 P.M. It will take 2 hours to hike to the camping spot and 1 hour to set up the camp. What is the latest time Dalton and his family can start hiking?
Mathematics
1 answer:
vagabundo [1.1K]2 years ago
6 0
4pm because it takes them 3 hours to get set and sunset is at 7pm so 7-3=4pm boom!
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mojhsa [17]

Answer:

D. 7 - 3 = 7

Step-by-step explanation:

hope it helps..

5 0
2 years ago
The sum of two consecutive odd integers is -120. find the two integers
astra-53 [7]
The numbers are 59 and 61
8 0
3 years ago
<img src="https://tex.z-dn.net/?f=%5Cfrac%7B3%7D%7Bx%2B7%7D%20%2B%5Cfrac%7B4%7D%7Bx-8%7D" id="TexFormula1" title="\frac{3}{x+7}
sattari [20]

{7x+4}/{x^2-x-56}

using common denominators

6 0
2 years ago
The given lengths are two sides of a right triangle. All three side lengths of the triangle are integers and together form a pyt
Leni [432]
If all three side lengths are INTEGERS and form PYTHAGOREAN TRIPLE then we know decimals are not allowed

if 24 and 51 are both legs then
24^{2} +  51^{2} =  x^{2}
x = 3177
and squre root of that gives us 56.364.... NOT an integer

So that means one of them is not a leg and since hypotenuse is longer than both legs, 51 must be the hypotenuse so to get the third side

51^{2} -  24^{2}  =  x^{2}[tex] [tex] x^{2}=2025
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7 0
2 years ago
Plz help me with this math and also explain
jasenka [17]

Step-by-step explanation:

<h2>[1]</h2>

  • SI = $250
  • Rate (R) = 12\sf \dfrac{1}{2} %
  • Time (t) = 4 years

\longrightarrow \tt { SI = \dfrac{PRT}{100} } \\

\longrightarrow \tt { 250 = \dfrac{P \times 12\cfrac{1}{2} \times 4}{100} } \\

\longrightarrow \tt { 250 = \dfrac{P \times \cfrac{25}{2} \times 4}{100} } \\

\longrightarrow \tt { 250 = \dfrac{P \times 25 \times 2}{100} } \\

\longrightarrow \tt { 250 = \dfrac{P \times 50}{100} } \\

\longrightarrow \tt { 250 \times 100 = P \times 50} \\

\longrightarrow \tt { 25000 = P \times 50} \\

\longrightarrow \tt { \dfrac{25000}{50} = P } \\

\longrightarrow \underline{\boxed{ \green{ \tt { \$ \; 500 = P }}}} \\

Therefore principal is $500.

<h2>__________________</h2>

<h2>[2]</h2>

  • 2/7 of the balls are red.
  • 3/5 of the balls are blue.
  • Rest are yellow.
  • Number of yellow balls = 36

Let the total number of balls be x.

→ Red balls + Blue balls + Yellow balls = Total number of balls

\longrightarrow \tt{ \dfrac{2}{7}x + \dfrac{3}{5}x + 36 = x} \\

\longrightarrow \tt{ \dfrac{10x + 21x + 1260}{35} = x} \\

\longrightarrow \tt{ \dfrac{31x + 1260}{35} = x} \\

\longrightarrow \tt{ 31x + 1260= 35x} \\

\longrightarrow \tt{ 1260= 35x-31x} \\

\longrightarrow \tt{ 1260= 4x} \\

\longrightarrow \tt{ \dfrac{1260 }{4}= x} \\

\longrightarrow \underline{\boxed{  \tt { 315 = x }}} \\

Total number of balls is 315.

A/Q,

3/5 of the balls are blue.

\longrightarrow \tt{ Balls_{(Blue)} =\dfrac{3 }{5}x} \\

\longrightarrow \tt{ Balls_{(Blue)} =\dfrac{3 }{5}(315)} \\

\longrightarrow \tt{ Balls_{(Blue)} = 3(63)} \\

\longrightarrow \underline{\boxed{ \green {\tt { Balls_{(Blue)} = 189 }}}} \\

8 0
3 years ago
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