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pogonyaev
3 years ago
14

You call the pizza store and find out that each pizza has 12 slices. you expect 16 people to come, and you estimate each person

will eat 3 slices. How many pizzas should you order?
Now use the formula to solve the problem.
x=number of people at the party
y=number of slices per pizza
z=number of pizzas
n=number of slices each person will eat
nx/y=z
Mathematics
1 answer:
zysi [14]3 years ago
4 0
Nx/y=z
3(16)/12=z
3x16=48/12=4
z=4
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3 years ago
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16x 2 + 8x - 15 Mathematics?
Gala2k [10]
If you're factoring, your answer is

(4x - 3)(4x + 5)

You'll work it out this way:

16x^2 + 8x - 15

Since there's no GCF here, you multiply the first and third terms, giving you -240. Your next step is to find two numbers that have a sum of 8 and a product of -240. These numbers are 20 and -12. Plug those in and you've got:

16x^2 + 20x - 12x - 15

From here you divide it into two binomials. These are (16x^2 + 20x) and (-12x - 15).
When you take out the greatest common factors (4x and -3), they become:

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Then you group what's outside of the parentheses together (4x - 3)
And bring what's inside of the parentheses down (4x + 5).
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(4x - 3)(4x + 5)
5 0
3 years ago
Suppose two $20 bills, three $10 bills, one $5 bill, and seven $1 bills are placed in a bag. If you were to pull a bill at rando
Korolek [52]

Answer:

Assuming that the $1 bill was pulled at random, then the expected value of the amount chosen is \frac{7}{13}.

Step-by-step explanation:

From the given question, the bag contains;

$1 bill = 7

$5 bill = 1

$10 bill = 3

$20 bill = 2

Total number of bills in the bag = 13

Pulling a bill at random, the bills would have an expected value as follows:

For $1 bill, the expected value = \frac{7}{13}

For $5 bill, expected value = \frac{1}{13}

For $10 bill, expected value = \frac{3}{13}

For $20 bill, the expected value = \frac{2}{13}

Assuming that the $1 bill was pulled at random, then the expected value of the amount chosen is \frac{7}{13}.

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According to the United States Census Bureau, on September 11, 2014, the population of the United States was increasing by 11 pe
Papessa [141]

Answer:

317,988,000

Step-by-step explanation:    

We have been given that according to the United States Census Bureau, on September 11, 2014, the population of the United States was increasing by 11 people every 12 seconds.

Let us find number of people increased in 1 minute as:

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Now, we will convert 11 years into minutes and multiply by 55 to find increase in population in 11 years.    

\text{11 years}=11\text{ years}\times \frac{365\text{ days}}{\text{year}}\times \frac{24\text{ hours}}{\text{days}}\times \frac{60\text{ min}}{\text{hour}}

\text{11 years}=11\times 365\times 24\times 60\text{ min}

\text{11 years}=5,781,600\text{ min}

Upon multiplying 5,781,600 by 55, we will get:

\text{Population increase in 11 years}=5,781,600\text{ min}\times \frac{55 \text{ people}}{\text{min}}

\text{Population increase in 11 years}=5,781,600\times 55 \text{ people}

\text{Population increase in 11 years}=317,988,000 \text{ people}

Therefore, the population of United States would increase 317,988,000 in 11 years.

4 0
3 years ago
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