Answer:
WHAT SOCIETY?!
Every night we'd still be squatting in caves, hunched around campfires, waiting for the leopards to pick us off....
It's hard to have a society when your means of communication are nearly zero and therefore can't sustain the dialogue necessary to develop the shared values needed to form a society.
Answer:
D. a claim that more people drink a certain brand of cola that others
Explanation:
Basta yan yung sagot ko
Answer:
- def check_subset(l1, l2):
- status = False
- count = 0
- if(len(l1) > len(l2)):
- for x in l2:
- for y in l1:
- if x == y:
- count += 1
-
- if(count == len(l2)):
- return True
- else:
- return False
-
- else:
- for x in l1:
- for y in l2:
- if x==y:
- count += 1
-
- if(count == len(l1)):
- return True
- else:
- return False
-
- print(check_subset([1,4,6], [1,2,3,4,5,6]))
- print(check_subset([2,5,7,9,8], [7,8]))
- print(check_subset([1, 5, 7], [1,4,6,78,12]))
Explanation:
The key idea of this solution is to create a count variable to track the number of the elements in a shorter list whose value can be found in another longer list.
Firstly, we need to check which list is shorter (Line 4). If the list 2 is shorter, we need to traverse through the list 2 in an outer loop (Line 5) and then create another inner loop to traverse through the longer list 1 (Line 6). If the current x value from list 2 is matched any value in list 1, increment the count variable by 1. After finishing the outer loop and inner loop, we shall be able to get the total count of elements in list 2 which can also be found in list 1. If the count is equal to the length of list 2, it means all elements in the list 2 are found in the list 1 and therefore it is a subset of list 1 and return true (Line 10-11) otherwise return false.
The similar process is applied to the situation where the list 1 is shorter than list 2 (Line 15-24)
If we test our function using three pairs of input lists (Line 26-28), we shall get the output as follows:
True
True
False
Solid is your answer for the day
Answer:
c-Either A or B
Explanation:
The non-inverting amplifier usually has the input voltage connected to the non-inverting input while the inverting input is connected to the output.
Both the unit gain amplifier and the voltage follower have an input voltage connected to the non-inverting input, and the inverting input connected to the output, so both are special cases of the non-inverting amplifier.
The correct answer is
c-Either A or B
