A Hardware is any physical device used in. You can touch hardware, but you cannot touch software. Hardware is physical, and software is virtual. (brainliest) ??
B.
it's literally common sense
<h2>
Answer:</h2>
Authorization specifies what a user can do, and access control enforces what a user can do.
<h2>
Explanation:</h2>
Authorization is simply granting access to an authenticated user of an application. It specifies what a user can and/or cannot do. For example, for a user to access their banking details in an online banking service, they have to be authorized by first authenticating them to prove their identity. Another example is in an organizational system where some users (normally called admins) can access certain database info whereas some other users (normally called the regular users) cannot.
Access control is used to enforce the policies dictated by authorization. In other words, access control enforces the policy of what a user can and/or cannot do. Access control makes authorization possible. It is sometimes called privileges or permissions. For example, the <em>security tab </em>in the operating system of Windows, allow to set access privileges for certain files and/or folders. Another example is in an organizational system where some files on the organization's server are configured in such a way that access to it is restricted and dependent on some further authorization.
// Variable to keep track of array size
int length = 0;
// Array itself
int array[] = {};
// while loop will take input in the array until a negative number is entered
while(input>=0){
stdin = new Scanner(System.in);
array[length] = stdin;
length +=1;
}
// int variable to terminate while loop
int i =0;
// keep track of index of output array
int y =0;
while(arr[i] != length){
// making output array
int output[]={}; bool flag;
// put the element in out put array considering if it the desired one
output[y] = array [i];
// Now check if it was the desired?
for(int z=1;z<=length;z++){
if(array[i+z]!=output[y]){
flag = true;
}
else
{
output[y]=0;
y+=1;
}
if(array[i+z+1]=output[y] && flag == true){
output[y] = array[i];
y+=1;
}
}
//output the array
for(int o=0;o<y;o++)
System.out.println(output[o];
Answer:
No you do not need a interent browzer to get to the internet.
Explanation:
