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Law Incorporation [45]
3 years ago
9

Find the image of the figure after a dilation with a point A as the centre by a scale factor of 0.75​

Mathematics
1 answer:
Kobotan [32]3 years ago
4 0

Answer:

Step-by-step explanation:

So the dilation of .75.

You want to find what each point is before the dilation.

A(-10,-14)

B(-10,14)

C(12,14)

D(12,-14)

So, we multiply these by the scale factor, 0.75.

(x,y) = (X x 0.75, y x 0.75)

A  = -10 x 0.75, -14 x 0.75

B= -10 x 0.75, 14 x 0.75

C = 12 x 0.75 , 14 x 0.75

D = 12 x 0.75 , -14 x 0.75

now, the image of the figure would be

A' ( -7.5, -10.5)

B' (-7.5, 10.5)

C' (9, 10.5)

D' (9, -10.5)

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39*10*100*1,000*0+37???? HELPPP
FromTheMoon [43]

Answer:

37

Step-by-step explanation:

Anything multiplied by 0 is 0 then you just add the 37

5 0
3 years ago
Please help! It’s Saturday and I only have this question left on my digital worksheet!
Natalija [7]

Answer:

<h2>The answer is option C</h2>

Step-by-step explanation:

<h3>\frac{ {6}^{ - 3} }{ {6}^{5} }</h3>

Using the rules of indices

Since the bases are the same and are dividing we subtract the exponents

That's

<h3>\frac{ {a}^{x} }{ {a}^{y} }  =  {a}^{x - y}</h3>

So we have

<h3>\frac{ {6}^{ - 3} }{ {6}^{5} }  =  {6}^{ -  3 - 5}  =  {6}^{ - 8}</h3>

Using the rules of indices

<h3>{x}^{ - y}  =  \frac{1}{ {x}^{y} }</h3>

So we have the final answer as

<h2>\frac{1}{ {6}^{8} }</h2>

Hope this helps you

4 0
3 years ago
Find the thirteenth term of an arithmetic sequence if the first term is 3 and the common difference is 3
lesya692 [45]

Answer:

39

Step-by-step explanation:

Formula for the nth term (an) = a1 + d(n - 1)  where a1 = the first term and d = common difference.

So here the 13th term = 3 + 3(13 - 1)

= 3 + 3*12

= 39  (answer).

8 0
3 years ago
See image attached below keeeeeeeeeeeeeeeeeeeed
emmasim [6.3K]

Answer:

.13%

68.26%

2.28%

47.72%

49.87%

34.13%

Step-by-step explanation:

1.) standardize by subtracting the mean and dividng by the standard deviation

(625-1000)/125= -3

go to a ztable to get .0013 or (1-.9987)

this is equal to .13%

2.)

875<x<1125

standardize both seperately and subtract them

(875-1000)/125= -1  whose probability is .1587 (or 1-.8413)

(1125-1000)/125= 1  whose probability is .8413

.8413-.1587= 68.26%

3.)

Find the probability that someone paid less than 1250 and take its compliment

(1250-1000)/125= 2 which has a probability of .9772

take its compliment (1-.9772)= .0228= 2.28%

4.)

Same process as question 2

(750-1000)/125= -2 which has a probability of (1-.9772) = .0228

(1000-1000)/125= 0 which has a probability of .5

.5-.0228= .4772= 47.72%

5.) same deal as the previous question

(625-1000)/125= -3 which has a probability of (1-.9987)= .0013

(1000-1000)/125= 0 which has a probability of .5

.5-.0013= .4987= 49.87%

6.)same deal the previous question

(875-1000)/125= -1 which has a probability of (1-.8413)=.1587

(1000-1000)/125= 0 which has a probability of .5

.5-.1587= .3413= 34.13%

4 0
3 years ago
Differentiate. Y=5x^2 +6x
blagie [28]
The answer to this question is y' = 10x^2 + 6. You have to use the power rule to bring the exponent down as a coefficient and then reduce the exponent by 1. Do it for all the terms using the sum rule for derivatives (derivative of a sum of the sum of its derivatives).
5 0
3 years ago
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