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ivanzaharov [21]
3 years ago
15

I don't understand math @ all please help

Mathematics
1 answer:
chubhunter [2.5K]3 years ago
7 0
More than likely it is c, because I looked over all the answers and c was the best one for the problem
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Examine the following graph, where P(x) is the preimage and I(x) is the image after a transformation.
Arisa [49]

Answer:

the 4th answer I(x) = P(x-4)

Step-by-step explanation:

the first 2 options are out, because just adding values to the functional result values changes the y value, and the curve is pushed up or down. but not to the side.

just imagine

I(x) = P(x-4) means that the function value of previously at x-4 happens now at x. 4 units "later" (or more to the right).

"x+4" would make the functional value at previously x+4 happen now at x. so, everything would shift to the left (happen "earlier").

therefore, the 4th answer option is correct.

3 0
2 years ago
One pound of ground beef is $3.09. How much is 4.5 pounds? Round to the nearest hundredth, if necessary.
olga55 [171]

Since 1 pound is $3.09, 4.5 pounds will be:

4.5*3.09=13.905

It says to round to nearest hundredth, so your answer is $13.91.

5 0
3 years ago
Read 2 more answers
I need help in this question that is in the photo
mihalych1998 [28]
The answer is A, 1. In the statement x^2 >x, if we try 4, 5 and 8 for x, we get 16, 25 and 64 for x^2. The statement is true. But if we try x = 1, when we square it we still have 1. Therefore for x=1, x^2>x is false.
7 0
3 years ago
Okay in this input and output function
Monica [59]
As the input goes up by 3, the output goes down by 1.
6 0
3 years ago
Write the equation of a circle with center at (3, -2), which also passes through the point (0, 2).
Airida [17]

\text{The equation of acircle:}\\\\(x-h)^2+(y-k)^2=r^2\\\\(h;\ k)-center\\r-radius\\\\\text{We have center}\ (3,\ -2)\to h=3\ \text{and}\ k=-2.\\\\\text{The radius is the distance between the points} (3,\ -2)\ \text{and}\ (0,\ 2).\\\\\text{The formula of a distance between two points:}\\\\d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\\\\text{Substitute:}\\\\d=\sqrt{(2-(-2))^2+(0-3)^2}=\sqrt{4^2+(-3)^2}=\sqrt{16+9}\\\\=\sqrt{25}=5\\\\Answer:\ \boxed{(x-3)^2+(y-(-2))^2=5^2\to\boxed{(x-3)^2+(y+2)^2=25}}

3 0
3 years ago
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