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igor_vitrenko [27]
1 year ago
15

Examine the following graph, where P(x) is the preimage and I(x) is the image after a transformation.

Mathematics
1 answer:
Arisa [49]1 year ago
3 0

Answer:

the 4th answer I(x) = P(x-4)

Step-by-step explanation:

the first 2 options are out, because just adding values to the functional result values changes the y value, and the curve is pushed up or down. but not to the side.

just imagine

I(x) = P(x-4) means that the function value of previously at x-4 happens now at x. 4 units "later" (or more to the right).

"x+4" would make the functional value at previously x+4 happen now at x. so, everything would shift to the left (happen "earlier").

therefore, the 4th answer option is correct.

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