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anyanavicka [17]
3 years ago
8

How is the answer -1? How do I get it?

Mathematics
2 answers:
UNO [17]3 years ago
8 0
When distributing the negative three into the parentheses, that canceled out the -5 and made it a positive 15
Lerok [7]3 years ago
8 0

5x- 3(x-5)=13

5x-3x+15=13

2x=-2

x is  -2

Your mistake is that you forgot to add when you multiply 3 and 5

and negative and negative make positive

hope this helps


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Irina18 [472]

Answer:

\bf C)\: -\cfrac{1}{32}

Step-by-step explanation:

\tt \cfrac{1}{2^{-2}x^{-3}y^5}

\tt x=2\\y=-4

~

Substitute ''x'' with '2' & 'y' with "-4":-

\tt \cfrac{1}{2^{-2}\times \:2^{-3}\left(-4\right)^5}

First let's solve \tt 2^{-2}\times \:\:2^{-3}\left(-4\right)^5

\tt 2^{-2}\times \:2^{-3}=\boxed{\cfrac{1}{32} }

\tt \cfrac{1}{32}\left(-4\right)^5

Calculate exponents:- -4^5= -1024

\tt \cfrac{1}{32}\left(-1024\right)

Remove parentheses, apply rule:- \tt a\left(-b\right)=-ab

\tt-\frac{1}{32}\times \:1024

\tt \cfrac{1}{32}\times \cfrac{1024}{1}

Apply fraction rule:-

\tt -\cfrac{1\times \:1024}{32\times \:1}

\tt \cfrac{1024}{32}

Divide numbers:-

\tt -32

Now that we're done factoring the denominator let's bring down the numerator which is ' 1 ':-

\tt -\cfrac{1}{32}\;\; \bf Answer

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2 years ago
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Answer:

In order to subtract a whole number from a fraction, you first have to turn the hole number into a mixed fraction.

Step-by-step explanation:

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They have to have like denominators

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Answer:

<u>Use cross-multiplication to solve these</u>

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