Answer:
Option 2: m∠1 = 147°, m∠2 = 80°, m∠3 = 148°
Step-by-step explanation:
Step 1: Consider triangle ABC from the picture attached below.
Lets find angle x
x + 47 + 33 = 180 (because all angles of a triangle are equal to 180°)
x = 100°
Angle x = Angle y = 100° (because vertically opposite angles are equal)
Step 2: Find angle 2
Angle 2 = 180 - angle x (because angle on a straight line is 180°)
Angle 2 = 180 - 100
Angle 2 = 80°
Step 3: Find angle z
48 + y + z = 180° (because all angles of a triangle are equal to 180°)
z = 32°
Angle 3 = 180 - angle z (because angle on a straight line is 180°)
Angle 3 = 180 - 32
Angle 3 = 148°
Step 4: Find angle 1
Angle 1 = 180 - 33 (because angle on a straight line is 180°)
Angle 1 = 147°
Therefore m∠1 = 147°, m∠2 = 80°, m∠3 = 148°
Option 2 is correct
!!
The minimum number of shirt they will sell to make the given profit is 192 shirts
<h3>Inequality expression</h3>
Inequalities are equations not separated by an equal sign.
If a cheerleading team plans to sell t-shirts as a fundraiser and the teams goal is to make profit of at least $1248 with each t-shirt sold at $6.50, then the equation required is;
6.50t ≥ 1246
Divide both sides by 6.50
6.50t/6.50 ≥1246/6.5
t ≥ 192
Hence the minimum number of shirt they will sell to make the given profit is 192 shirts
Learn more on inequality here: brainly.com/question/11613554
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Answer:
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Answer:
(a) 0.20
(b) 31%
(c) 2.52 seconds
Step-by-step explanation:
The random variable <em>Y</em> models the amount of time the subject has to wait for the light to flash.
The density curve represents that of an Uniform distribution with parameters <em>a</em> = 1 and <em>b</em> = 5.
So, 
(a)
The area under the density curve is always 1.
The length is 5 units.
Compute the height as follows:


Thus, the height of the density curve is 0.20.
(b)
Compute the value of P (Y > 3.75) as follows:
![P(Y>3.75)=\int\limits^{5}_{3.75} {\frac{1}{b-a}} \, dy \\\\=\int\limits^{5}_{3.75} {\frac{1}{5-1}} \, dy\\\\=\frac{1}{4}\times [y]^{5}_{3.75}\\\\=\frac{5-3.75}{4}\\\\=0.3125\\\\\approx 0.31](https://tex.z-dn.net/?f=P%28Y%3E3.75%29%3D%5Cint%5Climits%5E%7B5%7D_%7B3.75%7D%20%7B%5Cfrac%7B1%7D%7Bb-a%7D%7D%20%5C%2C%20dy%20%5C%5C%5C%5C%3D%5Cint%5Climits%5E%7B5%7D_%7B3.75%7D%20%7B%5Cfrac%7B1%7D%7B5-1%7D%7D%20%5C%2C%20dy%5C%5C%5C%5C%3D%5Cfrac%7B1%7D%7B4%7D%5Ctimes%20%5By%5D%5E%7B5%7D_%7B3.75%7D%5C%5C%5C%5C%3D%5Cfrac%7B5-3.75%7D%7B4%7D%5C%5C%5C%5C%3D0.3125%5C%5C%5C%5C%5Capprox%200.31)
Thus, the light will flash more than 3.75 seconds after the subject clicks "Start" 31% of the times.
(c)
Compute the 38th percentile as follows:

Thus, the 38th percentile is 2.52 seconds.
Y = 3/5x + b
3 = 3/5(-1) + b
3 = -3/5 + b, b = 3 3/5
Y = 3/5x + 3 3/5