Answer:
1:5
5:9
7:11
9:13
I think this is right in not sure though
Given:
1 inch : 18 kilometers
Let us use the ratio and proportion method:
a:b = c:d where ad = bc
0.8 inches is <u>14.4 kilometers</u>
1 : 18 = 0.8 : x
x = 0.8 * 18
x = 14.4 km
1.4 inches is <u>25.2 kilometers</u>
1: 18 = 1.4 : x
x = 18 * 1.4
x = 25.2 km
2.1 inches is <u>37.8 kilometers</u>
1 : 18 = 2.1 : x
x = 18 * 2.1
x = 37.8 km
Answer:
x + y = 4
Step-by-step explanation:
Given the 2 equations
3x + 4y = 10 → (1)
2x + 3y = 6 → (2)
Subtract (2) from (1) term by term on both sides
x + y = 4
Answer:
(E) 0.71
Step-by-step explanation:
Let's call A the event that a student has GPA of 3.5 or better, A' the event that a student has GPA lower than 3.5, B the event that a student is enrolled in at least one AP class and B' the event that a student is not taking any AP class.
So, the probability that the student has a GPA lower than 3.5 and is not taking any AP classes is calculated as:
P(A'∩B') = 1 - P(A∪B)
it means that the students that have a GPA lower than 3.5 and are not taking any AP classes are the complement of the students that have a GPA of 3.5 of better or are enrolled in at least one AP class.
Therefore, P(A∪B) is equal to:
P(A∪B) = P(A) + P(B) - P(A∩B)
Where the probability P(A) that a student has GPA of 3.5 or better is 0.25, the probability P(B) that a student is enrolled in at least one AP class is 0.16 and the probability P(A∩B) that a student has a GPA of 3.5 or better and is enrolled in at least one AP class is 0.12
So, P(A∪B) is equal to:
P(A∪B) = P(A) + P(B) - P(A∩B)
P(A∪B) = 0.25 + 0.16 - 0.12
P(A∪B) = 0.29
Finally, P(A'∩B') is equal to:
P(A'∩B') = 1 - P(A∪B)
P(A'∩B') = 1 - 0.29
P(A'∩B') = 0.71
