Using the fundamental theorem of calculas the derivative of function g(x)=
at x=0 is 
.
Given a function g(x)=.
We are required to find the derivative of the function g(x) at x=0.
Function is relationship between two or more variables expressed in equal to form. The values entered in a function are part of domain and the values which we get from the function after entering of values are part of codomain of function. Differentiation is the sensitivity to change of the function value with respect to a change in its variables.
g(x)=
Differentiating with respect to x.
d g(x)/dx=+0 [Differentiation of x is 1 and differentiation of constant is 0]
=
Hence using the fundamental theorem of calculas the derivative of function g(x)= at x=0 is .
The function given in the question is incomplete. The right function will be g(x)=.
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.
Answer:
-42
Step-by-step explanation:
If you withdraw an amount, it means that you are taking it out. On the other hand, if you were to deposit an amount, you are putting money in. Taking something out means that you have less of it, so -42 would be the answer. If you were to deposit an amount, the answer would be +42 since you are adding it in.
Answer:
100 ft^2
Step-by-step explanation:
The large upper rectangle has dimensions 12 ft by 23 ft, and thus has area 276 ft^2. The small lower rectangle is 15 ft by (12 - 7) ft, or 15 t by 5 ft, and thus has area 75 ft^2. The total area is
75 ft^2 + 25 ft^2, or 100 ft^2.
Answer:
x = 9
Step-by-step explanation:
Create an equation:
x = some number
and = add
other number = -15
x + (-15) = -6
remove () using rule
x - 15 = -6
add +15 to both sides
x = 9
Answer:
<h3>The possibilities of length and width of the rectangle are </h3><h3>x=1, y=0.24;</h3><h3>x=0.5, y=0.48;</h3><h3>x=0.25, y=0.96;</h3><h3>x=2, y=0.12</h3>
Step-by-step explanation:
Given that the area is 0.24 square meter
The area of a rectangle is given by
square units
Let x be the length and y be the width.
Since the area is 0.24 square meter, we have the equation:
, with x and y measures in meters
If we want to know some possibilities of x and y, we can assume a value for one of them, and then calculate the other one using the equation.
Now choosing some values for "x", we have:
Put x = 1
∴ y = 0.24
Now put x = 0.5 we get
∴ y = 0.48
Put x = 0.25
∴ y = 0.96
Put x = 2
∴ y = 0.12
