To find the product of (4x-5y)^2,
we can rewrite the problem as:
(4x-5y)(4x-5y) (two times because it is squared)
Now, time to use that old method we learned in middle school:
FOIL. (Firsts, Outers, Inners, and Lasts)
FOIL can help us greatly in this scenario.
Let's start by multiplying the 'Firsts' together:
4x * 4x = <em>16x^2</em>
Now, lets to the 'Outers':
4x * -5y = <em>-20xy</em>
Next, we can multiply the 'Inners':
-5y * 4x = <em>-20xy</em>
Finally, let's do the 'Lasts':
-5y * -5y = <em>25y</em>^2
Now, we can take the products of these equations from FOIL and combine like terms. We have: 16x^2, -20xy, -20xy, and 25y^2.
-20xy and -20xy make -40xy.
The final equation (product of (4x-5y)^2) is:
16x^2 - 40xy + 25y^2
Hope I helped! If any of my math is wrong, please report and let me know!
Have a good one.
Answer:
answer is -x^2-1+5
Step-by-step explanation:
so you can do it .
Answer:
Step-by-step explanation:
From the given information:
a) To express the weekly profit as a function of price
Cost =C(q) = 1500 + 10q
Revenue = p×q = (50 − 0.1q)×q = 50q - 0.1q²
Revenue = 50q - 0.1q²
Weekly profit = Revenue - Cost
P(q) = (50q -0.1q²) - (1500 + 10q)
P(q)= -0.1 q² + 40 q - 1500
However, q = 500 - 10 p using p = 50 − 0.1q
P= -0.1 (500 - 10 p)² + 40 (500 - 10 p) - 1500
P= -10 p² + 600 p - 6500
b)
The price at which the bottle of the wine must be sold to realise a maximum profit can be determined by finding the derivative and then set it to 0
P' = 0
= -20p+600 = 0
20p = 600
p = 600/20
p = $30
c)
The maximum profit that can be made by the producer is:
P= -10(30)² + 600(30) - 6500
P = - 9000 + 18000 - 6500
P = $2500
A decimal in the wrong place can change the value of a number completely for example
0.5 can be converted to 50 cents or 1/2 but if you change the decimal 0.05 converts to 5% or 1/20.