Answer:
10/8 or 1 and 2/8
Step-by-step explanation:
You can convert 2/4 into 4/8 then all you have to do from there is just add to get 10/8.
Hope I could help! :)
Answers: A) $44,944
B) $50,499.0784
Math: Using the percentage calculator linked below 6% of $40,000 is $2,400. Since you're getting your second raise after your first and since it is a 6% raise from what you're getting paid at that time we add pay raise 1 to your starting pay before calculating the 6% for pay raise 2. $40,000+$2,400=$42,400. 6% of $42,400 is $2,544. $42,400+$2,544=$44,944, Since that is two pay raises that would be your earnings at the end of year two (answer A).
We continue calculating 6% then adding that onto the total before calculating it for the next year for problem B.
6% of $44,944 is $2,696.64. $44,944+$2,696.64=$47,640.64.
6% of $47,640.64 is $2,858.4384. $47,640.64+$2,858.4384=$50,499.0784. That's answer B.
Hopefully you can figure out C on your own! I feel a little bad for giving a partial answer but I think you can do this!
Percentage calculator used-https://percentagecalculator.net/
Note: can't handle commas, remove all commas before entering data in.
tan( 20 ) + 4 Sin( 20 ) =
( Sin( 20 ) / Cos( 20 ) ) + 4 Sin( 20 ) =
Sin( 20 ) + 4 Sin( 20 ).Cos( 20 ) / Cos( 20 ) =
Sin( 20 ) + 2 × 2 Sin(20).Cos(20)/ Cos(20) =
Sin( 20 ) + 2 × Sin( 40 ) / Cos( 20 ) =
Sin( 20 ) + 2Sin( 40 ) / Cos( 20 ) =
Sin( 20 ) + 2Cos( 50 ) / Cos ( 20 ) =
Sin( 20 ) + 2Cos( 20 + 30 ) / Cos( 20 ) =
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2 × Cos( 30 + 20 ) =
2 × [ Cos(30).Cos(20) - Sin(30).Sin(20) ] =
2 × [ √3/2 × Cos(20) - 1/2 × Sin(20) ] =
√3 Cos(20) - Sin(20)
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Sin( 20 ) + 2Cos ( 20 + 30 ) / Cos( 20 ) =
Sin( 20 ) + √3 Cos(20) - Sin(20) / Cos(20) =
Sin(20) - Sin(20) + √3 Cos(20) / Cos(20) =
0 + √3 Cos(20) / Cos(20) =
√3 Cos(20) / Cos(20) =
Cos(20) simplifies from the numerator and denominator of fraction
√3 × 1 / 1 =
√3
And we're done ....
100 times 17 bc u have to count the shdded parts
Answer:
74.32
Step-by-step explanation:
Add the two together, and you have your answer b/c it's asking for the total length of the line
