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Otrada [13]
2 years ago
7

What is 8 ÷ 2(2 + 2) = i have been stuck on this problem for 1 year now Halp !!!

Mathematics
2 answers:
xxTIMURxx [149]2 years ago
7 0

Answer:

8÷2= 4 and (2+2)= 4 .....

Anika [276]2 years ago
4 0

Answer:

ok after reviewing this answer for the past 8 years i just figured it out

1(6)

Step-by-step explanation:

i know this may come as a huge shock however this is actually true. It's been a long emotionally journey finding this answer but please bear with me, as im crying really hard right now since I cannot believe I actually solved it. As unbelievable as it sounds I will not be providing work as i think my mind is too big and swag, but please believe me on this because im  literally the kid genius

edit: ok just ran this through my totally not paid for calculator with my mcdonalds money but it is actually 16 i am literally deleteing   my account this is so embarassing for me

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Need help asap please
Lelechka [254]

Answer:

The answer is row C

Step-by-step explanation:

6 - 3 = 3

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2 years ago
What value of x makes this equation true?
UkoKoshka [18]

Answer:

The correct answer is D

Step-by-step explanation:

-190 + -100 = -290

190 + -100 = 90

-10 + -100 = -110

10 + -100 = 90

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8 0
2 years ago
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A roller coaster carries riders up a ramp that is 39 meters long
sasho [114]

what do u have to search for?

5 0
3 years ago
Evaluate each of the following to three significant figures, and express each answer in SI units using an appropriate prefix: (a
Softa [21]

Answer:

a). 4.86\times 10^{-15} m

b). 4.21\times 10^{-2} m³

c). 7.00\times 10^{3} N²

Step-by-step explanation:

In this question we have to convert each option into SI units.

a). 4.86(10^{-6})^{2} mm

= 4.86\times (10^{-12})\times (10^{-3} ) m

= 4.86\times 10^{-15} m

b). (348 mm)³

= (348)^{3}\times (10^{-3})^{3} m³

= 42144192\times 10^{-9} m³

= 4.21\times 10^{-2} m³

c). (83700)^{2}\times (10^{-3})^{2} N²

= 700569\times 10^{4}\times 10^{-6} N²

= 7.00\times 10^{9}\times 10^{-6}N^{2}

= 7.00\times 10^{3} N²

7 0
2 years ago
In order to estimate the average time spent on the computer terminals per student at a local university, data were collected fro
VladimirAG [237]

Answer:

Margin of error  for a 95% of confidence intervals is 0.261

Step-by-step explanation:

<u>Step1:-</u>

 Sample n = 81 business students over a one-week period.

 Given the population standard deviation is 1.2 hours

 Confidence level of significance = 0.95

 Zₐ = 1.96

Margin of error (M.E) = \frac{Z_{\alpha  }S.D }{\sqrt{n} }

Given n=81 , σ =1.2 and  Zₐ = 1.96

<u>Step2:-</u>

<u />Margin of error (M.E) = \frac{Z_{\alpha  }S.D }{\sqrt{n} }<u />

<u />Margin of error (M.E) = \frac{1.96(1.2) }{\sqrt{81} }<u />

On calculating , we get

Margin of error = 0.261

<u>Conclusion:-</u>

Margin of error  for a 95% of confidence intervals is 0.261

<u />

4 0
3 years ago
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