There are 8 possible outcomes for a marble being drawn and numbered.
{1,2,3,4,5,6,7,8}
There are 4 possible outcomes for a card being selected from a standard deck.
{ <span>hearts, diamonds, clubs, spades}
So the number of outcomes in the sample space would be 8 x 4 = 32.
In the event "an even number is drawn", there are only 4 possible outcomes for a marble being drawn, {2,4,6,8}, whereas there are still 4 possible outcomes for a suit. So the number of outcomes in the event is 4 x 4 = 16.
</span><span>In the event "a number more than 2 is drawn and a red card is drawn", there are 6 possible outcomes for the marble being drawn, {3,4,5,6,7,8}, whereas there are only two possible suits for a card being selected as red, {heart, diamond}. So the number of outcomes in this event is 6 x 2 = 12.
In the event </span><span>"a number less than 3 is drawn or a club is not drawn", the number drawn could be 1 or 2 whereas a spade/heart/diamond could be selected. So the number of outcomes is 2 x 3 = 6.</span><span>
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Answer:
I hope this answer helps you
Answer:
4π/3 square units
Step-by-step explanation:
Triangle XYZ is equilateral,
The central angle of the sector is 120°, or 2π/3 radians.
The area of a sector of central angle β is given by
.. A = (1/2)r^2*β . . . . . . β in radians
.. A = (1/2)*2^2*(2π/3) = 4π/3 square units
Answer:
√3
Step-by-step explanation:
Spanish
Racionalización de denominadores 3 / v3 tres sobre raíz cuadrada de 3
da
Usando el método de índices
3 / √3 = 3¹ / 3¹ / ²
= 3¹ / 3⁰.⁵
= 3¹⁻¹ / ²
= 3 ¹ / ²
= √3
Esto también se puede resolver multiplicando tanto el numerador como el denominador por √3
3 / √3 * √3 / √3
= 3√3 / √3 * 3
= 3√3 / √9
= 3√3 / 3
Los tres se cancelan y nos queda √3
English
Rationalization of denominators 3 /v3 three over square root of 3
gives
Using the method of indices
3 / √3 = 3¹/ 3¹/²
= 3¹/ 3⁰.⁵
= 3¹⁻¹/²
=3 ¹/²
=√3
This can also be solved multiplying both the numerator and the denominator by √3
3 / √3 * √3/√3
= 3√3/ √3*3
= 3√3/ √9
= 3√3/ 3
The three are cancelled and we are left with √3
