3 x-intercepts:
1) x = -1
2) x = 3
3) x = 4
Answer:
C. x>4
Step-by-step explanation:
3/(x-4) > 0
3>0, so
x-4 >0
x > 4
Answer:
The value of x is 73.5.
Step-by-step explanation:
Given:
7/10=x/105.
Now, to find the value of 
So, to get the value of 
we use cross multiplication:
By cross multiplying we get:
By dividing both sides by 10 we get:
Therefore, the value of x is 73.5.
Answer:
The possible value for angle P will be 100
And sum will also 100 because it has only one value.
Step-by-step explanation:
Given:
angle R measures 40 degree and PQR is isosceles triangle.
To Find:
Measure angle P.
Solution:
The given triangle is isosceles hence it will have 2 same angle included in it.
And sum of all angles of a triangle is 180 degree.
let same angles be x and other be y
So ,
x+x+y=180.............. sum of all angles.
2x+y=180.
Now to find possible values for y ,with x=40,
2x+y=180
80+y=180
y=100
So being x= 40 y =100 which satisfy given angle R condition.
now let y=80,then x should satisfy 40 degree value, so
2x+80=180
2x=100
x=50
it doest not satisfy the given value hence possible for y will be 100.
Since x=40 degree.
1. Find the equation of the line AB. For reference, the answer is y=(-2/3)x+2.
2. Derive a formula for the area of the shaded rectange. It is A=xy (where x is the length and y is the height).
3. Replace "y" in A=xy with the formula for y: y= (-2/3)x+2:
A=x[(-2/3)x+2] This is a formula for Area A in terms of x only.
4. Since we want to maximize the shaded area, we take the derivative with respect to x of A=x[(-2/3)x+2] , or, equivalently, A=(-2/3)x^2 + 2x.
This results in (dA/dx) = (-4/3)x + 2.
5. Set this result = to 0 and solve for the critical value:
(dA/dx) = (-4/3)x + 2=0, or (4/3)x=2 This results in x=(3/4)(2)=3/2
6. Verify that this critical value x=3/2 does indeed maximize the area function.
7. Determine the area of the shaded rectangle for x=3/2, using the previously-derived formula A=(-2/3)x^2 + 2x.
The result is the max. area of the shaded rectangle.
