Ask question

Ask question

All categories

3 years ago

12

Larry has already read 60 pages out of a 400 page book. He wants to finish the book in the next 20 days. The equation 20x + 60 =

400 correctly models this scenario IF x represents...

2 answers:

chubhunter [2.5K]3 years ago

6 0

The ANSWER Represents DAYS

antiseptic1488 [7]3 years ago

4 0

Answer:

days

Step-by-step explanation:

You might be interested in

On another map the distance between saugerties and kingston is 2 inches. Whar would tge distance from saugerties to catskill be

Mariana [72]

The question is incomplete. The map is attached as a photo and here is the complete question:

a. What is the actual distance between Saugerties and

Kingston? ___________________________

b. Catskill is 15 miles from Saugerties. What would the

distance on the map be? ___________________________

c. On another map, the distance between Saugerties and

Kingston is 2 inches. What would the distance from Saugerties to

Catskill be on this map? __________________

Since you have asked the answer for part (c) only, here is the answer:

Answer:

<u>The distance from Saugerties to Catskill would be </u><u>3 inches</u><u> on this map.</u>

Step-by-step explanation:

On the given map, the distance between Saugerties and Kingston is 4 inches and the scale is <u>1 inch = 2.5 miles.</u>

To calculate the actual distance in miles between Saugerties and Kingston, consider the given scale:

1 inch ---------- 2.5 miles

4 inches ------ x miles

Cross multiplying:

1x = 2.5 x 4

x = 10 miles

The actual distance between Saugerties and Kingston is 10 miles.

On another map, the distance between Saugerties and Kingston is 2 inches. Which means the scale is 2 inches = 10 miles. So 1 inch = 10/2 = 5 miles

The scale on the other map is 1 inch = 5 miles.

Catskill is 15 miles from Saugerties (given in the previous part). So on the map:

1 inch -------- 5 miles

y inch ------- 15 miles

Cross multiplying:

15 = 5y

y = 15/5

<u>y = 3 inches.</u>

The distance from Saugerties to Catskill would be 3 inches on this map.

7 0

3 years ago

Need help!! what is the ewuation of the like shown?

Marta_Voda [28]

Answer:

<em><u>An</u></em> equation is y = 2x + 4.

Step-by-step explanation:

<em><u>ANOTHER</u></em> equation is y - 2 = 2(x + 1)

4 0

3 years ago

Please help!!!<br><br>what is 2+2=???

IrinaVladis [17]

The answer is 4 ok ok

6 0

3 years ago

Read 2 more answers

use the general slicing method to find the volume of The solid whose base is the triangle with vertices (0 comma 0 ), (15 comma

lyudmila [28]

Answer:

volume V of the solid

$\boxed{V=\displaystyle\frac{125\pi}{12}}$

Step-by-step explanation:

The situation is depicted in the picture attached

(see picture)

First, we divide the segment [0, 5] on the X-axis into n equal parts of length 5/n each

[0, 5/n], [5/n, 2(5/n)], [2(5/n), 3(5/n)],..., [(n-1)(5/n), 5]

Now, we slice our solid into n slices.

Each slice is a quarter of cylinder 5/n thick and has a radius of

-k(5/n) + 5 for each k = 1,2,..., n (see picture)

So the volume of each slice is

$\displaystyle\frac{\pi(-k(5/n) + 5 )^2*(5/n)}{4}$

for k=1,2,..., n

We then add up the volumes of all these slices

$\displaystyle\frac{\pi(-(5/n) + 5 )^2*(5/n)}{4}+\displaystyle\frac{\pi(-2(5/n) + 5 )^2*(5/n)}{4}+...+\displaystyle\frac{\pi(-n(5/n) + 5 )^2*(5/n)}{4}$

Notice that the last term of the sum vanishes. After making up the expression a little, we get

$\displaystyle\frac{5\pi}{4n}\left[(-(5/n)+5)^2+(-2(5/n)+5)^2+...+(-(n-1)(5/n)+5)^2\right]=\\\\\displaystyle\frac{5\pi}{4n}\displaystyle\sum_{k=1}^{n-1}(-k(5/n)+5)^2$

But

$\displaystyle\frac{5\pi}{4n}\displaystyle\sum_{k=1}^{n-1}(-k(5/n)+5)^2=\displaystyle\frac{5\pi}{4n}\displaystyle\sum_{k=1}^{n-1}((5/n)^2k^2-(50/n)k+25)=\\\\\displaystyle\frac{5\pi}{4n}\left((5/n)^2\displaystyle\sum_{k=1}^{n-1}k^2-(50/n)\displaystyle\sum_{k=1}^{n-1}k+25(n-1)\right)$

we also know that

$\displaystyle\sum_{k=1}^{n-1}k^2=\displaystyle\frac{n(n-1)(2n-1)}{6}$

and

$\displaystyle\sum_{k=1}^{n-1}k=\displaystyle\frac{n(n-1)}{2}$

so we have, after replacing and simplifying, the sum of the slices equals

$\displaystyle\frac{5\pi}{4n}\left((5/n)^2\displaystyle\sum_{k=1}^{n-1}k^2-(50/n)\displaystyle\sum_{k=1}^{n-1}k+25(n-1)\right)=\\\\=\displaystyle\frac{5\pi}{4n}\left(\displaystyle\frac{25}{n^2}.\displaystyle\frac{n(n-1)(2n-1)}{6}-\displaystyle\frac{50}{n}.\displaystyle\frac{n(n-1)}{2}+25(n-1)\right)=\\\\=\displaystyle\frac{125\pi}{24}.\displaystyle\frac{n(n-1)(2n-1)}{n^3}$

Now we take the limit when n tends to infinite (the slices get thinner and thinner)

$\displaystyle\frac{125\pi}{24}\displaystyle\lim_{n \rightarrow \infty}\displaystyle\frac{n(n-1)(2n-1)}{n^3}=\displaystyle\frac{125\pi}{24}\displaystyle\lim_{n \rightarrow \infty}(2-3/n+1/n^2)=\\\\=\displaystyle\frac{125\pi}{24}.2=\displaystyle\frac{125\pi}{12}$

and the volume V of our solid is

$\boxed{V=\displaystyle\frac{125\pi}{12}}$

3 0

3 years ago

Formula given in picture

yarga [219]

I think It's 0.9% I'm not sure though or 1.03%

4 0

3 years ago