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4 years ago

39. Three 12 a resistors are connected in parallel and then connected to a 6.0 V battery. Find

Physics

1 answer:

katen-ka-za [31]4 years ago

7 0

Answer:

39.) Current = 1.5 A

40.) B

Explanation:

Given that three 12 Ohms resistors are connected in parallel.

The equivalent resistance R will be

1/R = 1/R1 + 1/R2 + 1/R3

Substitute the values into the formula

1/R = 1/12 + 1/12 + 1/12

1/R = 3/12

Find the reciprocal of both sides

R = 12/3

R = 4 Ohms

From Ohm's law,

V = IR

Where V = 6v

Substitute V and the R into the formula and make current I the subject of formula

6 = I × 4

I = 6/4

I = 1.5 A

Therefore, the resulting current is 1.5 Ampere.

40.) If the devices and outlets in each circuit in a household are wired in parallel, The main reason for this is

Plugging in more devices decreases the total resistance on the circuit.

Because, the sum of resistance of resistors in parallel is less than the least resistance of a resistor is the circuit. Also, they will all share the same amount of voltage because there is no voltage drop.

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Which mass is undergoing to the greatest amount of acceleration ??

lina2011 [118]

Answer:

Option (3)

Explanation:

Formula used to calculate acceleration is,

F = ma

Where F = force exerted on a mass

m = mass

a = acceleration due to force exerted on the mass

Option (1),

When F = 100 N and m = 100 kg

100 = 100a

a = 1 m per sec²

Option (2)

For F = 1 N and m = 100 kg

1 = 100a

a = $\frac{1}{100}$

a = 0.01 m per sec²

Option (3)

For F = 100 N and m = 1 kg

100 = 1(a)

a = 100 m per sec²

Option (4)

For F = 1 N and m = 1 kg

1 = 1(a)

a = 1 m per sec²

Therefore. acceleration in Option (3) is the maximum.

4 0

4 years ago

Ahmed kept a balloon from his birthday for several days until it began to deflate and slowly sink to the ground. He wondered how

goldfiish [28.3K]

He should study the chapter about laws to get a better understanding about the laws that govern physical objects

8 0

3 years ago

Read 2 more answers

Two small objects each with a net charge of +Q exert a force of magnitude F on each other. We replace one of the objects with an

Alona [7]

Answer:

F'= 4F/9

Explanation:

Two small objects each with a net charge of +Q exert a force of magnitude F on each other. If r is the distance between them, then the force is given by :

$F=\dfrac{kQ^2}{r^2}$ ...(1)

Now, if one of the objects with another whose net charge is + 4Q is replaced and also the distance between +Q and +4Q charges is increased 3 times as far apart as they were. New force is given by :

$F'=\dfrac{kQ\times 4Q}{(3r)^2}\\\\F'=\dfrac{4kQ^2}{9r^2}$ .....(2)

Dividing equation (1) and (2), we get :

$\dfrac{F}{F'}=\dfrac{\dfrac{kQ^2}{r^2}}{\dfrac{4kQ^2}{9r^2}}\\\\\dfrac{F}{F'}=\dfrac{kQ^2}{r^2}\times \dfrac{9r^2}{4kQ^2}\\\\\dfrac{F}{F'}=\dfrac{9}{4}\\\\F'=\dfrac{4F}{9}$

Hence, the correct option is (d) i.e. " 4F/9"

7 0

3 years ago

What is the acceleration of an object that goes from 45m/s to 10 m/s in 5 seconds?

kipiarov [429]

Answer:

$\boxed {\boxed {\sf a= -7 \ m/s^2}}$

Explanation:

Acceleration is the change in velocity over time.

$a= \frac {v_f-v_i}{t}$

The object accelerates from 45 meters per second to 10 meters per second in 5 seconds. Therefore,

$v_f=10 \ m/s \\v_i= 45 \ m/s \\t= 5 \ s$

Substitute the values into the formula.

$a= \frac{ 10 \ m/s - 45 \ m/s}{5 \ s}$

Solve the numerator.

$a= \frac { -35 \ m/s}{5 \ s}$

Divide.

$a= -7 \ m/s/s$

$a= -7 \ m/s^2$

The acceleration of the object is -7 meters per square second. The acceleration is negative because the object's velocity decreases and the object slows down.

5 0

3 years ago

Three cars collide, a 1500 kg sports car, a 1750 kg family car, and a 1200 kg compact car. Which experiences the greatest change

sweet [91]

Answer:

Explanation:

This is because momentum is defined as p = mv

delta p = Force *time

neither velocity nor time is given so a conclusion cannot be made on which has the greatest momentum change.

5 0

3 years ago