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Phantasy [73]
3 years ago
5

Newton’s Third Law of Motion states that when one object exerts a force on a second object, the forces are __________________.

Physics
1 answer:
Veronika [31]3 years ago
3 0
Newton's Third Law of Motion states that when one object exerts a force on a second object, the forces are B. equal in magnitude and opposite in direction. 
His third law is - For every action, there is an equal reaction. 
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Problems with solar energy include _____.
german
First choice:  the inability of current technology to capture
large amounts of the Sun's energy

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Second choice:  the inability of current technology to store
captured solar energy

No.  We're pretty good at building batteries to store small amounts, or raising water to store large amounts.  Storage could be better and cheaper than it is, but we can store huge amounts of captured solar energy right now, so this isn't a major problem either.

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3 years ago
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Which of the following is not an element of installment credit?
Alex787 [66]

Answer:

c line of credit I believe

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Plot StartRoot 1.5 EndRoot and StartRoot 1.9 EndRoot on the number line to find which inequalities are true. Check all that appl
Vera_Pavlovna [14]

Answer:

A, B, C, E

Explanation:

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HELP!!! HURRY!!!!! 100 POINTS!!!!!!!!!
bagirrra123 [75]

what happens at Point C is sublimation. the increase in temperature affects the Vapour pressure soon as you can see the curve is increasing with increasing pressure there is increase in temperature that is the sublimation Curve

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3 years ago
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A single-turn circular loop of radius 6 cm is to produce a field at its center that will just cancel the earth's field of magnit
djverab [1.8K]

Answer:

The current is  I  = 6.68 \  A

Explanation:

From the question we are told that  

     The radius of the loop is  r =  6 \ cm  = 0.06 \ m

     The  earth's magnetic field is B_e =  0.7G=  0.7  G * \frac{1*10^{-4} T}{1 G}  = 0.7 *10^{-4} T

      The  number of turns is  N  =1

Generally the magnetic field generated by the current in the loop is mathematically represented as

        B  =  \frac{\mu_o  * N  *  I}{2 r }

Now for the earth's magnetic field to be canceled out the magnetic field generated by the loop must be equal to the magnetic field out the earth

         B  =  B_e

=>     B_e =  \frac{\mu_o  *  N  *  I  }{ 2 * r}

     Where  \mu is the permeability of free space with value  \mu _o  =   4\pi * 10^{-7} N/A^2

       0.7  *10^{-4}=  \frac{ 4\pi * 10^{-7}  * 1 * I}{2 * 0.06}

=>     I  =  \frac{2 *  0.06 *  0.7 *10^{-4}}{ 4\pi * 10^{-7} * 1}

       I  = 6.68 \  A

3 0
3 years ago
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