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valentina_108 [34]
3 years ago
7

HELLLPPPPP I dont understand this!! Picture is attached!! THANKS

Mathematics
1 answer:
sergij07 [2.7K]3 years ago
8 0

Answer:

27 =x

Step-by-step explanation:

We can use proportions to solve this problem.  Put the side of the small triangle over the same side of the large triangle.

x+8          10

------- = -------------------

2x-5          14

Using cross products

14 (x+8) = 10 (2x-5)

Distribute

14x+112 = 20x-50

Subtract 14x from each side

14x-14x +112 = 20x-50-14x

112 = 6x-50

Add 50 to each side

112+50 = 6x-50+50

162 = 6x

Divide by 6

162/6 =6x/6

27 =x

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Solve for x. 3^x−1=9^x+2 <br> Enter your answer in the box.
slava [35]

Answer:

-5 =x

Step-by-step explanation:

3^(x-1) = 9^(x+2)

Replace 9 with 3^2

3^(x-1) = 3^2^(x+2)

We know that a power to a power means the powers are multiplied

a^b^c = a^(b*c)

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When the bases are the same, the powers have to be the same

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Subtract 4 from each side

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4 0
3 years ago
Eden just bought a trough in the shape of a rectangular prism for her horses. She needs to know what volume of water to add to t
notsponge [240]

The volume of the trough is V(w) = w³ + 20w² - 429w and the rate of change of the volume over a width of 38 inches to 53 inches is 4695 in³/in

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more variables and numbers.

Let w represent the width, hence:

length = w + 33, height = w - 13

Volume (V) = w(w + 33)(w - 13) = w³ + 20w² - 429w

V(w) = w³ + 20w² - 429w

Rate of change = dV/dw = 3w² + 40w - 429

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When w = 53, dV/dw = 3(53)² + 40(53) - 429 = 10118

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The volume of the trough is V(w) = w³ + 20w² - 429w and the rate of change of the volume over a width of 38 inches to 53 inches is 4695 in³/in

Find out more on equation at: brainly.com/question/2972832

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Answer is on the attachment. Brainlist pls.

Step-by-step explanation:

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