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2 years ago

Write down an equation of the line that is perpendicular to y=2x+5 I will mark as brainliest

Mathematics

1 answer:

SVEN [57.7K]2 years ago

3 0

Answer:

y = -1/2x +5

Step-by-step explanation:

The perpendicular slope will be the negative reciprocal of the original slope

the reciprocal of 2 is 1/2, and the negative of that is -1/2

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Solve the equation using the zero product principle<br> (x-3)(x+6)=0

Wittaler [7]

Zero product states : if a * b = 0, then a = 0 and/or b = 0

(x - 3)(x + 6) = 0

x - 3 = 0
x = 3

x + 6 = 0
x = -6

so x = 3 and x = -6

7 0

4 years ago

Consider WXY and BCD with X= C, WX = BC, and WY = BD. Can it be concluded that WXY = BCD by SAS?

rosijanka [135]

Answer:

nswer:- B. No, because the corresponding congruent angles listed are not the included angles. Given:- ΔWXY and ΔBCD with ∠X ≅∠C, WX ≅ BC, and WY ≅ BD. We can see that ∠X and ∠C are not included angles by the corresponding equal sides.

6 0

3 years ago

Read 2 more answers

If Tanisha has $1000 to invest at 7% per annum compounded semiannually, how long will it be before she has $1600? If the co

Sphinxa [80]

Answer:

Using continuous interest 6.83 years before she has $1600.

Using continuous compounding, 6.71 years.

Step-by-step explanation:

Compound interest:

The compound interest formula is given by:

$A(t) = P(1 + \frac{r}{n})^{nt}$

Where A(t) is the amount of money after t years, P is the principal(the initial sum of money), r is the interest rate(as a decimal value), n is the number of times that interest is compounded per unit year and t is the time in years for which the money is invested or borrowed.

Continuous compounding:

The amount of money earned after t years in continuous interest is given by:

$P(t) = P(0)e^{rt}$

In which P(0) is the initial investment and r is the interest rate, as a decimal.

If Tanisha has $1000 to invest at 7% per annum compounded semiannually, how long will it be before she has $1600?

We have to find t for which $A(t) = 1600$ when $P = 1000, r = 0.07, n = 2$

$A(t) = P(1 + \frac{r}{n})^{nt}$

$1600 = 1000(1 + \frac{0.07}{2})^{2t}$

$(1.035)^{2t} = \frac{1600}{1000}$

$(1.035)^{2t} = 1.6$

$\log{1.035)^{2t}} = \log{1.6}$

$2t\log{1.035} = \log{1.6}$

$t = \frac{\log{1.6}}{2\log{1.035}}$

$t = 6.83$

Using continuous interest 6.83 years before she has $1600

If the compounding is continuous, how long will it be?

We have that $P(0) = 1000, r = 0.07$

Then

$P(t) = P(0)e^{rt}$

$1600 = 1000e^{0.07t}$

$e^{0.07t} = 1.6$

$\ln{e^{0.07t}} = \ln{1.6}$

$0.07t = \ln{1.6}$

$t = \frac{\ln{1.6}}{0.07}$

$t = 6.71$

Using continuous compounding, 6.71 years.

7 0

4 years ago

Assume that the random variable X is normally distributed, with mean μ = 110 and standard deviation σ = 20. Compute the probabil

kogti [31]

Answer:

P(X > 126) = 0.2119

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

$\mu = 110, \sigma = 20$