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Fed [463]
3 years ago
9

True or False ? The distance formula is equivalent to the Pythagorean theorem if you are

Mathematics
1 answer:
ElenaW [278]3 years ago
4 0

I believe that it is true due to it, the distance formula uses x and y coordinates. So, they're the same thing in two different types, or so..

____

I hope this helps, as always. I wish you the best of luck and have a nice day, friend..

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I need help ( no links ) ( picture attached)
olasank [31]

Answer:

120-(30+48)= 42

Step-by-step explanation:

7 0
3 years ago
The graph shows the solution for which inequalities?
Helen [10]

Answer:

Inequalities are,

y ≥ 4x + 2

y ≥ 2

Step-by-step explanation:

Solid yellow line of the graph attached passes through two points (0, -2) and (1, 2).

Let the equation of this line is,

y = mx + b

Slope of the line = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}

                      m = \frac{2+2}{1-0}

                      m = 4

Y-intercept 'b' = -2

Equation of the line will be,

y = 4x - 2

Since shaded area is on the left side of this solid line so the inequality representing this region will be,

y ≥ 4x - 2

Another line is a solid blue line parallel to the x-axis.

Shaded region (blue) above the line will be represented by,

y ≥ 2

Therefore, the common shaded area of these inequalities will be the solution of the given inequalities.

7 0
3 years ago
Pls help I don’t understand
dmitriy555 [2]

The answer is c. \frac{46}{9}

a. \frac{11}{5}=2.2 (2.2≠5.11) (2.2 is not equal to 5.11)

b. 5\frac{1}{8}=\frac{5}{8} or 0.625 (0.625≠5.11) (0.625 is not equal to 5.11)

c. \frac{46}{9} =5.11 (5.11=5.11) (5.11 is equal to 5.11)

Therefore c is the answer

4 0
3 years ago
I’m Really lost if I could get a answer it would be greatly appreciated
Nataly [62]
<h3>Answers:</h3>

f(g(x)) = \sqrt{x^2+5}+5\\\\g(f(x)) = x+30+10\sqrt{x-1}

================================================

Work Shown:

Part 1

f(x) = \sqrt{x-1}+5\\\\f(g(x)) = \sqrt{g(x)-1}+5\\\\f(g(x)) = \sqrt{x^2+6-1}+5\\\\f(g(x)) = \sqrt{x^2+5}+5\\\\

Notice how I replaced every x with g(x) in step 2. Then I plugged in g(x) = x^2+6 and simplified.

------------------

Part 2

g(x) = x^2+6\\\\g(f(x)) = \left(f(x)\right)^2+6\\\\g(f(x)) = \left(\sqrt{x-1}+5\right)^2+6\\\\g(f(x)) = \left(\sqrt{x-1}\right)^2+2*5*\sqrt{x-1}+\left(5\right)^2+6\\\\g(f(x)) = x-1+10\sqrt{x-1}+25+6\\\\g(f(x)) = x+30+10\sqrt{x-1}\\\\

In step 4, I used the rule (a+b)^2 = a^2+2ab+b^2

In this case, a = sqrt(x-1) and b = 5.

You could also use the box method as a visual way to expand out \left(\sqrt{x-1}+5\right)^2

6 0
3 years ago
A recipe calls for 1 3/4 cups of sugar. How many cups of sugar are needed if only 3/8 of the recipe is being made?
Katen [24]

Answer: 9/16

Step-by-step explanation:

7 0
3 years ago
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