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Ganezh [65]
3 years ago
10

Each week, Ms.Jones goes to the grocery store and estimates that she will spend $120. This week, she actually spent $90. What is

her percent error? (Round your answer to the nearest whole percent.)
Mathematics
2 answers:
bonufazy [111]3 years ago
6 0
There is a 25% error
horsena [70]3 years ago
4 0
I think there is a 25% percent error.
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He buys 4 pizzas oml that’s 20 characters now
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3 years ago
Difference of 8 Let's dig into this and find out for sure. First think of two numbers that have a difference of 8. Type the LARG
Serhud [2]

Answer:

<u>16</u>

Step-by-step explanation:

We need to find 2 numbers that have a difference of 8.

Let take's 16 and 8.

As we know :

⇒ 16 - 8

⇒ <u>8</u>

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The larger of these 2 numbers is <u>16</u>

5 0
1 year ago
Simplify f+g / f-g when f(x)= x-4 / x+9 and g(x)= x-9 / x+4
steposvetlana [31]

f(x)=\dfrac{x-4}{x+9};\ g(x)=\dfrac{x-9}{x+4}\\\\f(x)+g(x)=\dfrac{x-4}{x+9}+\dfrac{x-9}{x+4}=\dfrac{(x-4)(x+4)+(x-9)(x+9)}{(x+9)(x+4)}\\\\\text{use}\ a^2-b^2=(a-b)(a+b)\\\\=\dfrac{x^2-4^2+x^2-9^2}{(x+9)(x+4)}=\dfrac{2x^2-16-81}{(x+9)(x+4)}=\dfrac{2x^2-97}{(x+9)(x+4)}\\\\f(x)-g(x)=\dfrac{x-4}{x+9}-\dfrac{x-9}{x+4}=\dfrac{(x-4)(x+4)-(x-9)(x+9)}{(x+9)(x+4)}\\\\\text{use}\ a^2-b^2=(a-b)(a+b)\\\\=\dfrac{x^2-4^2-(x^2-9^2)}{(x+9)(x+4)}=\dfrac{x^2-16-x^2+81}{(x+9)(x+4)}=\dfrac{65}{(x+9)(x+4)}


\dfrac{f+g}{f-g}=(f+g):(f-g)=\dfrac{2x^2-97}{(x+9)(x+4)}:\dfrac{65}{(x+9)(x+4)}\\\\=\dfrac{2x^2-97}{(x+9)(x+4)}\cdot\dfrac{(x+9)(x+4)}{65}\\\\Answer:\ \boxed{\dfrac{f+g}{f-g}=\dfrac{2x^2-97}{65}}

6 0
3 years ago
Read 2 more answers
(Giving brainliest! Pls have at least one sentence to explain why you chose the answer :) )
Kryger [21]

Answer:

A

Step-by-step explanation:

Hope it helps

4 0
2 years ago
Read 2 more answers
Lizzy and Ella sold 10 boxes of cookies for $55.50. How much does each box of cookies cost? Show all your work and explain how y
densk [106]
55.50/ 10 boxes =5.50 that is  cost of 1 box. 
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3 years ago
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